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3 years ago

In triangle XYZ,

Mathematics

1 answer:

jenyasd209 [6]3 years ago

6 0

it is b, d, and e your welcome let me know if they are wrong but they were correct when i did it

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Help needed again . summer school issues

lorasvet [3.4K]

1) week 2 she spent $29.21
You would multiply the gallons of gas she bought by the price of each gallon.
2) $1.06 more because you would subtract week 1’s by week 4’s total

7 0

3 years ago

Simplify 3(3x-1)^2=21

scoray [572]

3(3x-1)^2=21

(3x-1)^2 = 7

3x-1 = square root of 7

3x = square root of 7 - 1

x = (square root of 7 - 1)/3

4 0

4 years ago

Read 2 more answers

Noah has a total of 47 video games he only buys action games in sports games he has 21 warehousing in the sports games how many

kicyunya [14]

Question is not proper;Proper question is given below;

Noah has a total of 47 video games. he only buys action games and sports games. He has 21 more action games than sports games. how many action games, a, and sports games, s, does he own?

Answer:

Noah has 34 action games and 13 sports games.

Step-by-step explanation:

Given:

Total number of games he has = 47

Let the number of action games be 'a'.

Let the number of sports game be 's'.

So we can say that;

Total number of games he has is equal to sum of the number of action games and the number of sports games.

framing in equation form we get;

$a+s = 47 \ \ \ \ \ eqaution \ 1$

Also Given:

He has 21 more action games than sports games.

so we can say that;

$a=s+21 \ \ \ equation\ 2$

Now Substituting equation 2 in equation 1 we get;

$a+s=47\\\\s+21+s=47\\\\2s+21=47$

Subtracting both side by 21 we get;

$2s+21-21=47-21\\\\2s = 26$

Dividing both side by 2 we get;

$\frac{2s}{2}=\frac{26}{2}\\\\s=13$

Now Substituting the value of 's' in equation 2 we get;

$a=s+21=13+21=34$

Hence Noah has 34 action games and 13 sports games.

4 0

3 years ago

What is 2/3 of 8 please

Veseljchak [2.6K]

8 * 2/3
16/3

Hope this helps!

7 0

3 years ago

Read 2 more answers

Plssss help

Andre45 [30]

Answer:

A) $\displaystyle \frac{1}{77}$ .
B) $\displaystyle \frac{12}{77}$ .
C) $\displaystyle \frac{4}{11}$ .

Step-by-step explanation:

All marbles here are identical. Also, the question isn't concerned about the order in which the marbles are drawn. Thus, all calculations here shall be combinations rather than permutations.

How many ways to choose three out of six identical red marbles without replacement?

$\displaystyle _6C_3 = c(6, 3) = {6\choose 3} = 20$ .

Note that these three expressions are equivalent. They all represent the number of ways to choose 3 out of 6 identical items without replacement.

How many ways to choose three out of all the 6 + 10 + 6 = 22 marbles?

$\displaystyle _{22} C_{3} = 1540$ .

The probability of choosing three red marbles out of these 22 marbles will be:

$\displaystyle \frac{\text{Number of ways for choosing three out of six red marbles}}{\text{Number of ways to choose three out of 22 marbles}} = \frac{20}{1540} = \frac{1}{77}$ .

How many ways to choose two out of six identical red marbles without replacement?

$\displaystyle _6 C_2 = 15$ .

How many ways to choose one out of 10 + 6 = 16 non-red marbles?

$_{16} C_1=16$ .

Choosing two red marbles does not influence the number of ways of choosing a non-red marble. Both event happen and are independent of each other. Apply the product rule to find the number of ways of choosing two red marbles and one non-red marble out of the pile of 22.

$_6 C_2 \cdot _{16} C_1= 240$ .

Probability:

$\displaystyle \frac{240}{1540} = \frac{12}{77}$ .

Double check that the order doesn't matter here.

None of the marbles are red. In other words, all three marbles are chosen out of a pile of 10 + 6 = 16 white and blue marbles. Number of ways to do so:

$_{16} C_{3} = 560$ .

Probability:

$\displaystyle \frac{560}{1540}= \frac{4}{11}$ .

5 0

4 years ago

Read 2 more answers