constant cost of 12
$1 for rides.
the number of rides you take is unknown, x
so its f(x) = 1x +12 or x+12
so if you rode 20 rides its
f(20) = 20+ 12 =32
Answer:
Step-by-step explanation:
16x^4y^-3z^4 / 36x^-2yz^0
16x^4y^-3z^4 = 16x^4z^4/y^3
36x^-2yz^0 = 36x^-2y(1) =36x^-2y = 36y/x^2
16x^4y^-3z^4 / 36x^-2yz^0
= (16x^4z^4/y^3) / (36y/x^2)
= 16x^4z^4/y^3 * x^2/36y
= (4/9)x^6z^4/y^4
or another way
fist multiply it out
f(x) = 4x^(3/5) - x^(8/5)
now differentiate knowing d/dx(x^n) = n x^(n-1)
to get
4*(3/5) x^(-2/5) - 8/5 x^(3/5)
simplify to get
12/5/x^(2/5) - 8/5 x^(3/5)
If this is what your looking for please give me brainiest, i have done this problem in the past so i know how to solve it :)
Part(A):
To solve the system of Linear equations using Substitution:
Consider the first equation, x+y=7 implies x=7-y
PArt(B): Use a graph to verify your answer to the system:
Using Desmos graphing calculator, graph the two equations.
This is the table....................
19-20 idk but ik the others
21.)0.785
22.)0
23.)-14.5
24.)7.838
