Question

⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ b(1)=−2 b(n)=b(n−1)−7 ​ Find the 3 rd 3 rd 3, start superscript, start text, r, d, end text, end superscript term in the sequence.

Answer 1

Answer:

-16

Step-by-step explanation:

Given the sequence:

b(n)=b(n−1)−7, where b(1)=−2

b(2)=b(2−1)−7

=b(1)−7

=-2-7

b(2)=-9

Therefore, the 3rd term of the sequence

b(3)=b(3−1)−7

=b(2)-7   (Recall b(2)=-9 from above)

=-9-7

b(3)=-16

The 3rd term of the sequence is -16.