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iVinArrow [24]
3 years ago
7

Rearrange w=3(2a+b) -4 to make A the subject

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
6 0

Answer:

a = \frac{w+4-3b}{6}

Step-by-step explanation:

Given

w = 3(2a + b) - 4 ( add 4 to both sides )

w + 4 = 3(2a + b) ← distribute

w + 4 = 6a + 3b ( isolate the term in a by subtracting 3b from both sides )

w + 4 - 3b = 6a ( divide both sides by 6 )

a = \frac{w+4-3b}{6}

olganol [36]3 years ago
4 0

Answer:

a=((w/3)-b)/2

Step-by-step explanation:

w=3(2a+b)

Divide both sides by 3

w/3=2a+b

Subtract b from both sides

(w/3)-b=2a

Divide both sides by 2

((w/3)-b)/2=a

State your answer

a=((w/3)-b)/2

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Answer:

Step-by-step explanation:

34.546.567

3 0
3 years ago
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An electronics hobbyist has three electronic parts cabinets with two drawers each.
Andrews [41]

Answer:

a) 0.5 = 50% probability that an NPN transistor will be selected.

b) 0.3333 = 33.33% probability that it came from the cabinet that contains both types

c) 66.67% probability that it comes from the cabinet that contains only NPN transistors

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

a) What is the probability that an NPN transistor will be selected?

1/3 probability that the first cabinet is chosen. This cabinet has two transistors, both of which are NPN, so 100% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, both of which are PNP, so 0% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, one of which is NPN, so 50% probability of selecting a NPN transistor.

So

p = \frac{1}{3}*1 + \frac{1}{3}*0 + \frac{1}{3}*0.5 = \frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = 0.5

0.5 = 50% probability that an NPN transistor will be selected.

b) Given that the hobbyist selects an NPN transistor, what is the probability that it came from the cabinet that contains both types?

Here we use the conditional probability formula.

Event A: NPN transistor

Event B: From the third cabinet.

50% probability that an NPN transistor will be selected, so P(A) = 0.5.

1/6 probability that it is from the third cabinet and NPN, so P(A \cap B) = \frac{1}{6}

The desired probability is:

P(B|A) = \frac{\frac{1}{6}}{0.5} = 0.3333

0.3333 = 33.33% probability that it came from the cabinet that contains both types.

c) Given that an NPN transistor is selected what is the probability that it comes from the cabinet that contains only NPN transistors?

Either it comes from the cabinet with only NPN transistors, or it comes from the cabinet with both types of transistors. The sum of the probabilities of these outcomes is 100%. So

x + 33.33 = 100

x = 66.67

66.67% probability that it comes from the cabinet that contains only NPN transistors

6 0
3 years ago
The area of a triangle is 14 square units it has a side length of a and b what is the value of b if a is 1/5
Ilia_Sergeevich [38]

Answer:

140 ft

Step-by-step explanation:

Given data

Area= 14 square feet

Height a = 1/5 ft

Base b=????

We know that the area of a triangle is given as

Area= (1/2)B*H

substitute

14= 1/2* B* 1/5

14= B/10

cross multiply

B= 140

 

Hence the base is 140 ft

7 0
3 years ago
Is there an error in this statement If x2 = 25, then x = 5.
katen-ka-za [31]
Yes there is an error in this statement.

because x^2 = 25 
so x = 5...this is one condition

Another condition is x = -5
(-5)^2 = 25 (this is also true)
7 0
3 years ago
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Below are two parallel lines with a third line intersecting them
olga_2 [115]

Answer:

x = 122

Step-by-step explanation:

x = 122 because of alternate interior angles

3 0
3 years ago
Read 2 more answers
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