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2 years ago

5

Roberto must make his costume for his school play. He needs a piece of fabric that is 2 2/3 yards long and 1 1/2 yards wide. Wha

t is the piece of fabric Roberto needs?

1 answer:

erik [133]2 years ago

7 0

Answer:

He will need 8.34 yards of fabric.

Step-by-step explanation:

Given that,

The length of the fabric, l = 2 2/3 yards = 8/3 yards

The width of the fabric, b = 1 1/2 yards = 3/2 yards

We need to find the piece of fabric Roberto needs. It is equal to the perimeter of the fabric such that,

$P=2(l+b)\\\\P=2(\dfrac{8}{3}+\dfrac{3}{2})\\\\P=2\times \dfrac{25}{6}\\\\P=8.34\ \text{yards}$

So, he will need 8.34 yards of fabric.

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<u>Step-by-step explanation:</u>

f(x) = 2x g(x) = x² - 1

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g(f(x)) = (2x)² - 1

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PLEASE HURRY: A biology class has a total of 31 students. The number of females is 17 less than the number of males. How many ma

Soloha48 [4]

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7 females, 24 males

Step-by-step explanation:

I solved it by using this equation:

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then divide by 2 on both sides:

x=7

then I added 7 to 17 to find the number of males:

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2 years ago

Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of

Shalnov [3]

Answer:

$Owl= 67.14ft$

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

$22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}$

$22^{\circ} 8'6'' = 22.135^{\circ}$

$30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}$

$30^{\circ} 40'30'' = 30.675^{\circ}$

Considering Jason's position:

$tan(22.135^{\circ}) = \frac{H}{x + 48}$

Where x = distance between the tree and Alison

Make H the subject

$H = (x + 48)tan(22.135^{\circ})$

Considering Alison's position

$tan(30.675^{\circ}) = \frac{H}{x}$

Make H the subject

$H = xtan(30.675^{\circ})$

$H = H$

$(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})$

$(x + 48) *0.4068 = x* 0.5932$

Open bracket

$x *0.4068 + 48 *0.4068 = 0.5932x$

$0.4068x + 19.5264 = 0.5932x$

Collect Like Terms

$-0.5932x+0.4068x = -19.5264$

$-0.1864x = -19.5264$

$0.1864x = 19.5264$

Make x the subject

$x = \frac{19.5264}{0.1864}$

$x = 104.76$

Substitute 104.76 for x in $H = xtan(30.675^{\circ})$

$H = 104.76 * tan(30.675^{\circ})$

$H = 104.76 * 0.5932$

$H = 62.14$

The above represents the height of the tree.

The height of the owl is:

$Owl= H + 5$

$Owl= 62.14 + 5$

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Answer:

Step-by-step explanation:

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