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bagirrra123 [75]
3 years ago
15

Please look at the picture for the question

Mathematics
1 answer:
eduard3 years ago
8 0

Answer:

-4.9

Step-by-step explanation:

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It's an isosceles triangle, so the angles at the base are congruent:


m\anlge WXY=m\angle WZY


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Therefore we have the equation:


m\angle YWZ+90^o+17^o=180^o\\\\m\angle YWZ+107^o=180^o\ \ \ |-107^o\\\\m\angle YWZ=73^o



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Find the circumference of the circle
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5 0
2 years ago
Read 2 more answers
Please help!! 20 POINTS
shepuryov [24]
<h2>Hello!</h2>

The answers are:

First image:

The answer is the second option, the angles is 53\°

Second image:

The answer is the third option:

\frac{5}{13}

Third image:

The length of the adjacent leg is the first option:

8\sqrt{2}units

Fourth image:

The answer is the fourth option, 72\°

Fifth image:

The answer is the fourth option, DF (hypothenuse) is equal to 25 units.

<h2>Why?</h2>

To solve these problems, we need to use the following trigonometric identities and the Pythagorean Theorem, since we are working with right triangles.

Tan(\alpha)=\frac{y}{x}\\\\(Tan(\alpha))^{-1} =(\frac{y}{x})^{-1}\\\\\alpha =Arctan(\frac{y}{x})

Sin(\alpha)=\frac{opposite}{hypothenuse}

Pythagorean Theorem:

c^{2}=a^{2} +b^{2}

So, solving we have:

First image:

We are given a right triangle that has the following lengths:

base=x=6units\\height=y=8units\\hypothenuse=10units

Then, calculating we have:

\alpha =Arctan(\frac{y}{x})\\\\\alpha =Arctan(\frac{8}{6})\\\\\alpha =Arctan(1.33)\\\\\alpha =53\°

Hence, the answer is the second option, the angles is 53\°

Second image:

We are given a right triangle that has the following lengths:

base=x=12units\\height=y=5units\\hypothenuse=13units

Then calculating the sin ratio, we have:

Sin(\alpha)=\frac{opposite}{hypothenuse}

Sin(\alpha)=\frac{5}{13}

Thence, the answer is the third option:

\frac{5}{13}

Third Image:

We are given the following information:

hypothenuse=16units\\\\\alpha =45\°

Then, calculating one of the angle legs, since both will have the same length, using the sine trigonometric identity, we have:

Sin(\alpha)=\frac{Opposite}{Hypothenuse}\\ \\Sin(45\°)=\frac{Opposite}{16}\\\\Opposite=Sin(45\°)*16\\\\Opposite=\frac{\sqrt{2} }{2}*16=8\sqrt{2}

Hence, the answer is the first option the length of the adjacent leg is

Opposite=\frac{\sqrt{2} }{2}*16=8\sqrt{2}units

Fourth image:

We are given the following information:

base=x=9units\\height=y=3units

To calculate the angle at the B vertex, first, we need to calculate the angle at the C vertex, and then, calculate the B vertex by the following way:

Since the sum of all the interior angles of a triangle are equal to 180°, we have that:

180\°=Angle_{B}+Angle{C}+90\°

Angle_{B}=180\° -90\°-Angle_{C}

So, calculating the angle at the C vertex, we have:

\alpha =Arctan(\frac{y}{x})

\alpha =Arctan(\frac{3}{9})

\alpha =Arctan(0.33)=18.26\°

Then, calculating the angle at the B vertex, we have:

Angle_{B}=180\° -90\°-18.26\°=71.74\°=71.8\°=72\°

Hence, the answer is the fourth option, 72\°

Fifth image:

We are given the following information:

base=x=24units\\height=y=7units

Now, to calculate the distance DF (hypothenuse) we need to use the Pythagorean Theorem:

c^{2}=a^{2} +b^{2} \\\\hypothenuse^{2}=adjacent^{2}+opposite^{2}\\\\\sqrt{hypothenuse^{2}}=\sqrt{adjacent^{2}+opposite^{2}}\\\\hypothenuse=\sqrt{adjacent^{2}+opposite^{2}}

Then, substituting we have:

hypothenuse=\sqrt{24^{2}+(7)^{2}}

hypothenuse=\sqrt{576+49}=\sqrt{625}

hypothenuse=\sqrt{625}

hypothenuse=25units

Hence, the answer is the fourth option, DF (hypothenuse) is equal to 25 units.

Have a nice day!

4 0
3 years ago
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