Answer:
Explanation:
1). Ca(NO₃)₂ + KI → CaI + K(NO₃)₂
This equation is incorrect.
When Ca⁺⁺ reacts with I⁻, final product is CaI₂
And when K⁺ react with NO₃⁻, final product is KNO₃
Hence the equation will be,
Ca(NO₃)₂ + KI → CaI₂ + KNO₃
Now we have to balance this equation.
Ca(NO₃)₂ + 2KI → CaI₂ + KNO₃
↓
Ca(NO₃)₂ + 2KI → CaI₂ + 2KNO₃
2). Ca(NO₃)₂ + KOH → CaOH + K(NO₃)₂
This equation is incorrect,
Since the reaction of Ca⁺⁺ with OH⁻ gives the final product Ca(OH)₂
And final product of K⁺ and NO₃⁻ is KNO₃
Therefore, the equation will be,
Ca(NO₃)₂ + KOH → Ca(OH)₂ + KNO₃
Now we will balance this equation by changing the coefficients of the molecules until the number of atoms on both the sides become equal.
Ca(NO₃)₂ + KOH → Ca(OH)₂ + 2KNO₃
↓
Ca(NO₃)₂ + 2KOH → Ca(OH)₂ + 2KNO₃
3). Ca(NO₃)₂ + Na₂C₂O₄ → CaC₂O₄ + 2Na(NO₃)₂
This equation is incorrect,
Since the reaction of Na⁺ and NO₃⁻ gives the final product NaNO₃.
Therefore, the correct equation will be,
Ca(NO₃)₂ + Na₂C₂O₄ → CaC₂O₄ + 2NaNO₃
This equation is in the balanced form.
