Please help with Chem I DON'T HAVE ENOUGH TIME!

Chemistry

2 answers:

Kamila [148]2 years ago

7 0

We are given:

Mass of water: 119 grams

We know that one mole of a gas occupies 22.4L of volume

Number of moles of water:

Number of moles = given mass / Molar mass

Number of moles = 119 / 18 [molar mass of water = 18 grams/mol]

Number of moles = 6.61 moles

Volume occupied:

Volume = number of moles * 22.4 L

Volume = 6.61 * 22.4

Volume = 148L

Volume (in mL) = 1.48 * 10⁻¹ mL

FinnZ [79.3K]2 years ago

6 0

As 1 L = 1000 g

so 119 grams = 0.119000 L

Hope it is helpful to u

If yes then plz mark me brainlest

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Answer:

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2 years ago

If you have a 1500 g aluminum pot, how much heat energy is needed to raise its temperature by 100°C?

Nataly [62]

The heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ.

The heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.

Explanation:

The heat energy required to raise the temperature of any body can be obtained from the specific heat formula. As this formula states that the heat energy required to raise the temperature of the body is directly proportional to the product of mass of the body, specific heat capacity of the material and temperature change experienced by the material.

So in this problem, the mass of the aluminium is given as m = 1500 g, the specific heat of the aluminium is 0.900 J/g °C. Then as it is stated that the temperature is raised by 100 °C, so the pots are heat to increase by 100 °C from its initial temperature. This means the difference in temperature will be 100°C (ΔT = 100°C).

Then, the heat energy required to raise the temperature will be

$q = m*c*del T = 1500 * 0.900 * 100 = 135000 = 135 kJ$

Thus, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100 °C is 135 kJ.

Similarly, the mass of copper pot is given as 1500 g, the specific heat capacity of copper is 0.385 and the difference in temperature is 100 °C.

Then, the heat energy required to raise its temperature will be

$q = m*c*del T = 1500 * 0.385 * 100 = 57750 = 57.75 kJ$

And the heat energy required to raise the temperature of 1500 g of copper pot by 100°C is 57.75 kJ.

So, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ. And the heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.