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lyudmila [28]
3 years ago
8

You used 300 grams of Na2CO3 to wash one load of laundry. How many moles of laundry detergent did you use?

Chemistry
1 answer:
Bas_tet [7]3 years ago
3 0

Answer: The number of moles of laundry detergent used is, 2.83 moles.

Explanation : Given,

Mass of Na_2CO_3 = 300 g

Molar mass of Na_2CO_3 = 106 g/mol

Formula used :

\text{Moles of }Na_2CO_3=\frac{\text{Given mass }Na_2CO_3}{\text{Molar mass }Na_2CO_3}

Now put all the given values in this formula, we get:

\text{Moles of }Na_2CO_3=\frac{300g}{106g/mol}

\text{Moles of }Na_2CO_3=2.83mol

Therefore, the number of moles of laundry detergent used is, 2.83 moles.

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2 years ago
Calculate the concentrations of all species present in a 0.26 M solution of ethylammonium chloride (C2H5NH3Cl).
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0.00000223

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pKa for C2H5NH3+ = 10.7

pKw = 14.0

pKa + pKb = pKw

10.7 + pKb = 14.0

pKb = 14.0 - 10.7

pKb = 3.30

C2H5NH3Cl is a salt of ethylamine and HCl so it will dissolve in water to produce  C2H5NH3^+ + Cl^-

The base hydrolysis reaction:  C2H5NH3^+(aq) + H2O(l) <=> C2H5NH2(aq) + H3O^+(aq)

This reaction is described by Kb.

Kb = [C2H5NH2][H3O^+]/[C2H5NH3^+]

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so [C2H5NH3^+] = 0.26 - x

Kb = x^2/(0.26 - x) = 2.00 x 10^-11  

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We get:  x^2 + 2.00 x 10^-11x - 4.99 x 10^-12 = 0

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x = 2.23 x 10^-6 M = [C2H5NH2] = [H3O^+]

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[C2H5NH3^+] = 0.26 M = [Cl^-]

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pH = -log [H3O^+] = -log(2.23 x 10^-6) = 5.65

Ka is the acid dissociation constant

Kb is the base dissociation constant

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