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Kaylis [27]
2 years ago
11

In the Galapagos Islands, finches on different islands have beaks of different shapes, which help them gather the food that grow

s on the island where they live. The different types of beaks are what kind of adaptation?
A. structural adaptation
B. seasonal adaptation
C. behavioral adaptation
D. environmental adaptation
Chemistry
1 answer:
scZoUnD [109]2 years ago
7 0

Answer:

A. structural adaptation

Explanation:

Hope This Helps!!

God Bless!!

~DuffyDuck~

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How many liquids are found on the periodic table?<br><br><br><br> 1
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There are six liquids found on the periodic table.

1. Bromine

2. Mercury

3. Caesium

4. Gallium

5. Rubidium

6. Francium

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3 years ago
Which or these equations is balanced H2SO4 + 2Al &gt; Al2(SO4)3 + H2 or 2KCl + Pb(NO3)2 &gt; 2KNO3 + PbCl2
Dmitry_Shevchenko [17]

Balancing of chemical equation is essential because of the law of conservation of mass, which states that the mass of a system can not be created or removed.

The second equation is balanced

2KCl_(_a_q_) +Pb(NO_3)_2_(_a_q_) ==> 2KNO_3_(-a_q_) + PbCl_2(_a_q_)

This is because the number of elements of each atom in the product side equal the number of elements of each atom on the reactant side.

The first equation is not balanced

H_2SO_4 _(_a_q) + 2Al_(_s_) ==> Al(SO_4)_3_(_a_q_) + H_2_(_g_)

This is because there is 1 molecule of SO_4^{-2} on reactant side as compared to 3 molecules of SO_4^{-2}

To balance the equation we add a coefficient of 3 on sulphuric acid (H_2SO_4) and a coefficient of 3 on hydrogen (H_2)

3H_2SO_4_(_a_q_) + 2Al_(_s_) ==> Al(SO_4)_3_(_a_q_) + 3H_2_(_g_)

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3 years ago
In this photograph what rock formation is presented by the blue lines?
Effectus [21]

It is representing syncline rock formation

there are two rock formation based on fold formation : syncline and anticline

In syncline rock formation there is fold like trough unlike anticline where it is like crust

In syncline the fold is downward as shown in photo and the new rock is outer fold and old at inner side

3 0
3 years ago
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The electrical conductivities of the following 0.100 M solutions were measured in an apparatus that contained a light bulb as th
Rufina [12.5K]

Answer:

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Explanation:

The electrical conductivities of the solutions will depend on the concentration of ions in solution.

Al(NO₃)₃ solution contains 0.1 M of Al³⁺ ions and 0.3 M of NO₃⁻ ions

KI solution contains 0.1 M of K⁺ ions and 0.1 M of I⁻ ions

HF solution contains less than 0.1 M of H⁺ ions and less then 0.1 M of F⁻ ions, because the HF acid will not dissociate completely

CH₃OH practically it does not dissociate, so in the solution will not be electrical conductive (comparative with the other solutions)

The solutions in order of decreasing intensity of the bulb are ranked as following:

Al(NO₃)₃ >  KI > HF > CH₃OH

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Answer:

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