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Mrrafil [7]
3 years ago
5

Keratinocytes begin to die in the stratum granulosum. Keratinocytes begin to die in the stratum granulosum. True False

Chemistry
1 answer:
Scrat [10]3 years ago
6 0

Answer:

FALSE

Explanation:

Keratinocytes begin to die in the stratum granulosum is False.

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The cube has a mass of 72.9 g.<br><br> What is its density in g/cm3? <br><br> What substance is it?
sashaice [31]
If the cube is 3 cm on each side, then it has a volume of 27 cm^3 (3 x 3 x 3). Density is mass divided by volume, so its density is 72.9/27 = 2.7 g/cm^3. 

<span>Going by the density, the cube is made of Aluminium - density is a fairly unique quantity</span>
6 0
3 years ago
Do you think that all foods containing carbohydrates are healthful? Explain plz:(
deff fn [24]

Answer:

Yes

Explanation:

because some foods have carbohydrates but are healthy

8 0
3 years ago
This type of pollution will decay naturally
butalik [34]
Withdrawal is the answer to your question.
3 0
3 years ago
Final volume of Argon gas:
DerKrebs [107]

Answer:

6.78 × 10⁻³ L

Explanation:

Step 1: Write the balanced equation

Mg₃N₂(s) + 3 H₂O(g) ⇒ 3 MgO(s) + 2 NH₃(g)

Step 2: Calculate the moles corresponding to 10.2 mL (0.0102 L) of H₂O(g)

At STP, 1 mole of H₂O(g) has a volume of 22.4 L.

0.0102 L × 1 mol/22.4 L = 4.55 × 10⁻⁴ mol

Step 3: Calculate the moles of NH₃(g) formed from 4.55 × 10⁻⁴ moles of H₂O(g)

The molar ratio of H₂O to NH₃ is 3:2. The moles of NH₃ produced are 2/3 × 4.55 × 10⁻⁴ mol = 3.03 × 10⁻⁴ mol.

Step 4: Calculate the volume corresponding to 3.03 × 10⁻⁴ moles of NH₃

At STP, 1 mole of NH₃(g) has a volume of 22.4 L.

3.03 × 10⁻⁴ mol × 22.4 L/mol = 6.78 × 10⁻³ L

3 0
3 years ago
___ may be rinsed over materials to was off explosive residue. A) water B) bleach C) acid D) acetone
Sergio [31]

Answer: D.

Explanation: D. Acetone, Acetone may be rinsed over materials to wash off the explosive residue.

Hope this helps :)

4 0
3 years ago
Read 2 more answers
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