Answer:
120.575 kJ is the activation energy for the souring process.
Explanation:
The formula for an activation energy is given as:
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%20R%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= rate constant at 
= 
= rate constant at 
= 
= activation energy for the reaction = ?
R = gas constant = 8.314 J/mole.K
= initial temperature = 
= final temperature = 
Now put all the given values in this formula, we get:l
![\log (\frac{k}{40k})=\frac{Ea}{2.303\times 8.314 J/mol K}[\frac{1}{298K}-\frac{1}{277 K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7Bk%7D%7B40k%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%208.314%20J%2Fmol%20K%7D%5B%5Cfrac%7B1%7D%7B298K%7D-%5Cfrac%7B1%7D%7B277%20K%7D%5D)
120.575 kJ is the activation energy for the souring process.
The answer would be: <span>D. Kb for HS–
</span>
Kb is the dissociation constant of an acid/base molecule. The word b in Kb is base, which means the formula should have an OH- ion inside it. Ka would be the opposite of Kb where the formula has H+ ion.
In this question, the formula is: [H2S][OH-]/ [HS-]
Since there are OH- ion. Since H2S is acid and HS- is base, I think it should be <span>Kb for HS–
</span>
Answer:
I will give them advice, that do the power of flame low....
Explanation:
thanks.
The amount of 1,3-dimethyl urea produced would be 32,458 grams or 32.458 kg while that of carbon dioxide would be 16,214 grams of 16.214 kg
<h3>Stoichiometric problem</h3>
From the equation of the reaction, the mole ratio of methyl isocyanate with the products is 2:1 respectively.
Mole of 42,000 kg of methyl isocyanate = 42000/57 = 736.84 moles
Equivalent mole of 1,3-dimethyl urea = 736.84/2 =368.42 moles
Equivaent mole of carbon dioxide = 736.84/2 =368.42moles
Mass of 368.42 moles 1,3-dimethyl urea = 368.42 x 88.1 = 32,458 grams or 32.458 kg
Mass of 368.42 moles of carbon dioxide = 368.42 x 44.01 = 16,214 grams of 16.214 kg
More on stoichiometric problems can be found here: brainly.com/question/14465605
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Answer:
Nitrogen (N), carbon (C), hydrogen (H) and oxygen (O).
Explanation:
Hello,
Given the shown organic compound, we refer to types of atoms to the elements present in the compound, thus, we find nitrogen (N), carbon (C), hydrogen (H) and oxygen (O) that are bonded via single or double bonds in such compound.
Let's remember that compounds like that, having those elements are mainly found in biochemical substances such as proteins, a very important source of benefits for our body.
Regards.
