Answer:
Equipment = $16,000
Notes payable = $18,000
Explanation:
Total assets = Land + Equipment + Supplies + cash + prepaid rent
Equipment = Total assets - Land - Supplies - cash - prepaid rent
= $37,500 - $9,000 - $2,100 - $7,200 - $3,200
= $16,000
Total assets = Total liabilities = Shareholder's equity + salaries payable + notes payable + accounts payable
$37,500 = $13,500 + $4,300 + notes payable + $1,700
Notes payable = $37,500 - $13,500 - $4,300 - $1,700
= $18,000
Therefore, the value of equipment is $16,000 and the value of notes payable is $18,000.
answer:oa.
Explanation:
its just oa its the definition
The right answer for the question that is being asked and shown above is that: "• set marketing objectives." The first step in the process of creating a marketing plan is to <span>set marketing objectives. The group must know the goals and objectives why they are making a business or something.</span>
The complete question is as follows:
The admission directory of Big City University has a novel idea. He proposed using the IQ scores of current students as a marketing tool. The university agrees to provide him with enough money to administer IQ tests to 50 students. So the director gives the IQ test to an SRS of 50 of the university’s 5000 freshman. The mean IQ score for the sample is xbar=112. The IQ test he administered is known to have a σ of 15. What is the 95% Confidence Interval about the mean? What can the director say about the mean score of the population of all 5000 freshman?
Answer: The 95% confidence interval about the mean is
.
The director can say that he is 95% confident that the mean IQ score of the 5000 freshmen lies between 107.84 and 116.16.
We follow these steps to arrive at the answer:
Since the population standard deviation of the IQ test is known, we can use the Z scores to find the confidence interval.
The formula for the confidence interval about the mean is:

In the equation above, X bar is known as the point estimate and the second term is known as Margin of Error.
The Critical Value of Z at the 95% confidence level is 1.96.
Substituting the values in the question in the equation above we have,


