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Tems11 [23]
3 years ago
7

Will mark brainliest! The triangles shown below must be congruent, true or false

Mathematics
2 answers:
olchik [2.2K]3 years ago
8 0
True because they have the same size angles
sergejj [24]3 years ago
6 0

Answer:

Step-by-step explanation:

False

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The area of a bulletin board is 55 ft2. The length is nine feet less than four times the width. Find the length and the width, i
galben [10]

Answer:

The length and width are 11ft and 5ft respectively

Step-by-step explanation:

let the

length = L

Width = W

Area = LW = 55

The length is nine feet less than four times the width

L = 4W - 9

W (4W - 9) = 55

4W^2 - 9W -55 = 0

4W^2 - 20W + 11W - 55 = 0

4W(W - 5) + 11(W - 5) = 0

(W - 5)(4W + 11) = 0

W - 5 = 0 , 4W + 11=0

W = 5 or  - 11/4

since the width cannot be negative, W = 5

LW = 55

L = 55/5

L = 11

The length and width are 11ft and 5ft respectively.

7 0
3 years ago
Consider the points A(5, 3t+2, 2), B(1, 3t, 2), and C(1, 4t, 3). Find the angle ∠ABC given that the dot product of the vectors B
Vilka [71]

Answer:

66.42°

Step-by-step explanation:

<u>Given:</u>

A(5, 3t+2, 2)

B(1, 3t, 2)

C(1, 4t, 3)

BA • BC = 4

Step 1: Find t.

First we have to find vectors BA and BC. We do that by subtracting the coordinates of the initial point from the coordinates of the terminal point.

In vector BA B is the initial point and A is the terminal point.

BA = OA - OB = (5-1, 3t+2-3t, 2-2) = (4, 2, 0)

BC = OC - OB = (1-1, 4t-3t, 3-2) = (0, t, 1)

Now we can find t because we know that BA • BC = 4

BA • BC = 4

To find dot product we calculate the sum of the produts of the corresponding components.

BA • BC = (4)(0) + (2)(t) + (0)(1)

4 = (4)(0) + (2)(t) + (0)(1)

4 = 0 + 2t + 0

4 = 2t

2 = t

t = 2

Now we know that:

BA = (4, 2, 0)

BC = (0, 2, 1)

Step 2: Find the angle ∠ABC.

Dot product: a • b = |a| |b| cos(angle)

BA • BC = 4

|BA| |BC| cos(angle) = 4

To get magnitudes we square each compoment of the vector and sum them together. Then square root.

|BA| = \sqrt{4^2 + 2^2 + 0^2} = \sqrt{20} = 2\sqrt{5}

|BC| = \sqrt{0^2 + 2^2 + 1^2} = \sqrt{5}

2\sqrt{5}\sqrt{5}\cos{(m\angle{ABC})} = 4

10\cos{(m\angle{ABC})} = 4

\cos(m\angle{ABC}) = \frac{4}{10}=\frac{2}{5}

m\angle{ABC} = cos^{-1}{(\frac{2}{5})}

m\angle{ABC} = 66.4218^{\circ}

Rounded to two decimal places:

m\angle{ABC} = 66.42^\circ

3 0
2 years ago
This is my last question
mariarad [96]

Answer: B

Step-by-step explanation:because my teacher said she having trouble

5 0
3 years ago
I need help with B!!
statuscvo [17]
400 grams of trail mix
5 0
3 years ago
Read 2 more answers
A square billboard has an area of 625 ft squared. What is the length of the side of the billboard?
goldenfox [79]

Answer:

figured it out is 25

Step-by-step explanation:

hope this helps:)

3 0
3 years ago
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