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Finger [1]
3 years ago
15

Which figures are polygons

Mathematics
1 answer:
alexira [117]3 years ago
4 0

<em><u>Polygon:</u></em> a figure formed by coplanar segments

with one distinct interior region

Figure A, Figure B, and Figure D would be considered polygons.

Notice that those figures I mentioned above are

composed of line segments, and nothing else.

In addition, these figures don't have two separate

interior regions and figures that do aren't polygons.

Figure C would not be a polygon because

it's formed by a curve rather than line segments.

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To make 20 pancakes you have to use 3 eggs. how many eggs do you use to make 100 pancakes?
SashulF [63]
3/20 = 0.15
0.15 * 100 = 15
You would need to use 15 eggs for 100 pancakes.
8 0
3 years ago
At a college, 71% of courses have final exams and 45% of courses require research papers. Suppose that 26% of courses have a res
Degger [83]

Answer:

.9 or 90%

.1 or 10%

Step-by-step explanation:

E= Exam

P=Paper

E= .71

P= .45

E∩P=.26

A.) E∪P=?

E∪P= E+P-E∩P

.71+.45-.26= .9

B.) E'∩P' = (E∪P)'

(E∪P)' = 1-.9 = .1

3 0
3 years ago
50 points please help!!
igomit [66]
I’m really not to sure sorry about that
8 0
3 years ago
Read 2 more answers
Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
7 0
4 years ago
WILL GIVE BRAINLIEST! PLS HELP!!!
velikii [3]

Answer: 140m

Step-by-step explanation:

8 0
3 years ago
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