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vekshin1
4 years ago
7

please help!!! i really need the answer to this question, ill mark you as brainleist I need to find tha angle​

Mathematics
2 answers:
zheka24 [161]4 years ago
8 0

Answer:

MKL = 105

Step-by-step explanation:

The two angles are supplementary so the add to 180

2n+5 + 3n = 180

Combine like terms

5n+5 = 180

Subtract 5 from each side

5n+5 = 180-5

5n = 175

divide by 5

5n/5 = 175/5

n = 35

We want to find angle MKL

MKL = 3n = 3*35

MKL = 3*35

MKL = 105

kvv77 [185]4 years ago
3 0

Answer:

MLK is equal to 105

Step-by-step explanation:

2n+5 + 3n = 180 (straight line)

Step 1: Combine the like terms

5n+5 = 180

Step 2: Subtract 5 from each side

= 105

<em><u>MKL = 3n </u></em>

<em><u>= 3*35 </u></em>

<em><u>final answer = 105</u></em>

<em><u /></em>

<u><em>Please mark as brainliest, I need a few more :D</em></u>

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Please help.. Answer number 34 and 35. For number 34 find the measures of the numbered angles in each isosceles trapezoid. For n
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Answer:

33. m∠1 = 135°, ∠3 = 45°, ∠2 = 135°

34. m∠1 = 80°, m∠2 = 100°, m∠3 = 100°

35. m∠1 = 90°, m∠2 = 25°

Step-by-step explanation:

33. The given parameters of the isosceles trapezoid are;

The measure of one of the base angles = 45°

For an isosceles trapezoid, the base angles are equal, therefore, we have;

The measure of the other base angle = m∠3 = 45°

Similarly, m∠1 = m∠2

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∴ 45° + m∠3 + m∠1 + m∠2 = 360°

By substituting the known values, we have;

45° + 45° + m∠1 + m∠2 = 360°

From m∠1 = m∠2, we have;

45° + 45° + m∠1 + m∠1 = 90° + 2·m∠1 = 360°

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34. The measure of the base angles = 80°

∴ The measure of the other base angle = m∠1 = 80°

m∠2 = m∠3

80° + m∠1 + m∠2 + m∠3 = 360°

∴ 80° + 80° + 2·m∠2 = 360°

m∠2 = (360° - (80° + 80°))/2 = 100°

m∠2 = 100° = m∠3

35. The kite comprises of two half isosceles triangles

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Therefore, m∠1 = 90°

The diagonals bisect the angles at the vertices (Kite theorem)

Therefore, we have;

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m∠2 = 180° - (65° + 90°) = 25°

m∠2 = 25°.

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