AB = 6 cm, AC = 12 cm, CD = ?
In triangle ABC, ∠CBA = 90°, therefore in triangle BCD ∠CBD = 90° also.
Since ∠BDC = 55°, ∠CBD = 90°, and there are 180 degrees in a triangle, we know ∠DCB = 180 - 55 - 90 = 35°
In order to find ∠BCA, use the law of sines:
sin(∠BCA)/BA = sin(∠CBA)/CA
sin(∠BCA)/6 cm = sin(90)/12 cm
sin(∠BCA) = 6*(1)/12 = 0.5
∠BCA = arcsin(0.5) = 30° or 150°
We know the sum of all angles in a triangle must be 180°, so we choose the value 30° for ∠BCA
Now add ∠BCA (30°) to ∠DCB = 35° to find ∠DCA.
∠DCA = 30 + 35 = 65°
Since triangle DCA has 180°, we know ∠CAD = 180 - ∠DCA - ∠ADC = 180 - 65 - 55 = 60°
In triangle DCA we now have all three angles and one side, so we can use the law of sines to find the length of DC.
12cm/sin(∠ADC) = DC/sin(∠DCA)
12cm/sin(55°) = DC/sin(60°)
DC = 12cm*sin(60°)/sin(55°)
DC = 12.686 cm
Answer:
Conrad had 56 sales on Monday , 168 sales on Tuesday and 504 sales on Wednesday.
Step-by-step explanation:
Let x be the no. of sales on Monday
We are given that On Tuesday Conrad had 3 times as many sales as on Monday.
So, Conrad had sales on Tuesday = 3x
We are also given that On Wednesday, he had 9 times as many sales as on Monday.
So, Conrad had sales on Wednesday = 9x
Over the three days, he had a total of 728 sales
So, x+3x+9x=728
13x=728
x=56
Conrad had sales on Tuesday = 3x =3(56)=168
Conrad had sales on Wednesday = 9x=9(56)=504
Hence Conrad had 56 sales on Monday , 168 sales on Tuesday and 504 sales on Wednesday.
To complete the square:
we take the coefficient ox "x" (which in this problem is -20)
we divide it by 2
square that number
then add it to both sides of the equation
-20 / 2 = -10
-10^2 = 100
then we add 100 to both sides of the equation:
x^2 -20x
x^2 -20x +100 = 100
******************************************************
To get the roots of the equation, we take the square root of both sides:
(x -10) * (x-10) = 10
(x-10) = square root (10)
x-10 =
<span>
<span>
<span>
3.1622776602
</span>
</span>
</span>
x1 =
<span>
<span>
<span>
13.1622776602
</span>
and don't forget that square root of 10 also equals </span></span><span><span><span> -3.1622776602
</span>
</span>
</span>
x2 = 10
-<span>
<span>
<span>
3.1622776602
x2 = </span></span></span>
<span>
<span>
<span>
6.8377223398
</span>
</span>
</span>
Answer:
It is Third quardant in Graph
So if you want to fit the y-intercepts or "b", on the y-axis you should go by 25's [0, 25, 50, 75, 100...]
If the x-axis <u>does not have to</u> follow the same pattern (25's), you should go by 5's [0, 5, 10, 15, 20...]
y = 7x + 50
y = 2x + 175
First I would plot the y-intercepts for each equation, then plot a few points with x = 5, 10, 15 Then draw a straight line.
The point where the two lines meet/cross paths is your solution. It should be (25, 225) The x-axis is the number of miles, and the y-axis is the total cost. So Truck driver A and B would arrive/be at the same place/meet in 25 miles at the same cost of $225
