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Rus_ich [418]
3 years ago
12

Simplify: {[(16 ÷ 4) × (2 × 6)] ÷ 6} + 4 =

Mathematics
1 answer:
borishaifa [10]3 years ago
4 0

Answer:

12

Step-by-step explanation:

divided 16 by 4 which is 4. then multiply 2 by 6, which is 12. then multiply 4 by 12. Remember to always do ( ) first. 4 by 12 is 48. Then do 48 divided by 6 which is 8. then add 8+4 which is 12.

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for his long distance phone service, lamar pays a $3 monthly fee plus 11 cents per minute. last month, lamar's long distance bil
e-lub [12.9K]
Let the number of minutes be = x.

Cost per minute = 11 cents = 0.11

Phone Bill = Monthly fee  +    0.11* x 

Substituting from the question

20.82 = 3 + 0.11x

3 + 0.11x = 20.82

0.11x = 20.82 - 3

0.11x = 17.82

x = 17.82/0.11

x = 162  

<span>Lamar was billed for 162 minutes.</span>
4 0
3 years ago
Determine the Type I error if the null hypothesis, H0, is: an electrician claims that no more than 10% of homes in the city are
kap26 [50]

Answer : There are no more than 10% of homes in the city are not up to the current electric codes but actually we do not have evidence to accept it.

Explanation:

The Type I error occurs when the null hypothesis is true but we reject it.

Given null hypothesis : H_0 : an electrician claims that no more than 10% of homes in the city are not up to the current electric codes.

The Type I error for the given situation is that there are no more than 10% of homes in the city are not up to the current electric codes but actually we do not have evidence to accept it.

3 0
3 years ago
The profit (P) in dollars, for a company is modeled by the function P(x)=-750x^2+15,000x,where x is the number of items produced
OLEGan [10]
-750x^2+15000x

But x must be a natural number, so the answer is x>20.
5 0
3 years ago
The average monthly cell phone bill was reported to be $50.07 by the U.S. Wireless Industry. Random Sampling of a large cell pho
zalisa [80]

Answer:

The null and alternative hypotheses are:

H_{0}:\mu= 50.07

H_{a}:\mu>50.07

Under the null hypothesis, the test statistic is:

t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}} }

Where:

\bar{x} = 52.86 is the sample mean

s=7.0132 is the sample standard deviation

n=10 is the sample size

\therefore t=\frac{52.86-50.07}{\frac{7.0132}{\sqrt{10}} }    

          =1.26

Now, the right tailed t critical value at 0.05 significance level for df = n-1 = 10-1 = 9 is:

t_{critical}=1.833

Since the t statistic is less than the t critical value at 0.05 significance level, therefore,we fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the average phone bill has increased.


4 0
3 years ago
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zysi [14]

Answer:

77 cubed in.

Step-by-step explanation:

I think it is 77 cubed inches because the formula is V-bh

4 0
2 years ago
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