<h3>
Answer:</h3><h3>If you know one ratio in a proportion , you can use that information to find values in the other equivalent ratio. </h3>
Answer:
a) <u>90 pitches total</u>
b) <u>27 hits</u>
c) <u>63 pitches (either ball or strike)</u>
Step-by-step explanation:
Every pitch is:
BALL, STRIKE, HIT
(one of the 3)
a)
Given, 60% of total pitches were strikes, that is 54 of them. So we can say:
54 is 60% of total
Let total be "t", so we can write:
54 = 60% * t
Solving for "t":

Hence, <u>total 90 pitches</u>
<u></u>
b)
60% = strikes
10% = balls
Remaining = 60 + 10 = 70
100 - 70 = 30%
So, 30% of total were hits.
30% of 90
0.3 * 90
<u>27 hits</u>
<u></u>
c)
We know 10% were balls, so
0.10 * 90 = 9 balls
We know 54 were strikes
So, either ball or strike = 9 + 54 = 63
<u>63 pitches (either ball or strike)</u>
Answer:
Ah, this is an example of the distribution property, as you would need to distribute the 5 to the 8 and 3. Here's the step-by-step process:

<em>Let's first multiply the 5 and 8</em>

<em>Now, the 5 and 3</em>

We now have two whole numbers, and therefore our answer:
40 + 15
Answer:
a < -1
Step-by-step explanation:
Okay, so we are given this equation:
t(x) = ax^5 + 2
Lets plug in -2 as x and see what happens.. t(x) can be 66..
= 66
-32a + 2 = 66
-32a = 64
a = -2
A is less than -1,
a < -1
Answer:
7.36e+11
Step-by-step explanation: