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Minchanka [31]
3 years ago
15

Factorise fully the following 2x+8

Mathematics
2 answers:
kakasveta [241]3 years ago
7 0

Answer:

it cant be solved

Step-by-step explanation:

please a brainliest please

Annette [7]3 years ago
5 0
2x +8= 2(x+4)
Where 2 is the common factor.
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On a school trip to a theme park, 4 busses each carry 70 students.
DanielleElmas [232]

Answer:

165 Students Have No Made Plans For Lunch.

Step-by-step explanation:

According To the Question,

  • Given,On a school trip to a theme park, 4 busses each carry 70 students Then Total Number Of Students on a trip is 70×4=280 Students.
  • And,35% of the students are bringing their own lunch. Thus,35% Of 280 Students is 98 Students. Then Remaining 182 Students not bring their own lunch.

Now, 17 of the students are buying lunch when they get to the theme park. Thus students Who have not made plans for lunch is 182-17⇒165Students

7 0
3 years ago
Factor the following expression: 16z+20
Evgen [1.6K]

Answer:

4z + 5

Step-by-step explanation:

16 and 20 are both dividable by 4, so you divide them both by four and then you have your answer

3 0
2 years ago
Read 2 more answers
2/3x-2=7 answer…………………
marishachu [46]

Answer:

Enter a problem...

Algebra Examples

Popular Problems Algebra Solve for x 2/3x-2=7

2

3

x

−

2

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7

Combine

2

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and

x

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2

x

3

−

2

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7

Move all terms not containing

x

to the right side of the equation.

Tap for more steps...

2

x

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=

9

Multiply both sides of the equation by

3

2

.

3

2

⋅

2

x

3

=

3

2

⋅

9

Simplify both sides of the equation.

Tap for more steps...

x

=

27

2

The result can be shown in multiple forms.

Exact Form:

x

=

27

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Decimal Form:

x

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13.5

Mixed Number Form:

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Step-by-step explanation:

Thank's………………………………

5 0
2 years ago
A lake polluted by bacteria is treated with an antibacterial chemical. Aftertdays, thenumber N of bacteria per milliliter of wat
jeyben [28]

Answer:

N(1)=50 is a minimum

N(15)=4391.7 is a maximum

Step-by-step explanation:

<u>Extrema values of functions </u>

If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.  

We are given a function (corrected)

N(t) = 20(t^2-lnt^2)+ 30

N(t) = 20(t^2-2lnt)+ 30

(a)

First, we take its derivative

N'(t) = 20(2t-\frac{2}{t})

Solve N'(t)=0

20(2t-\frac{2}{t})=0

Simplifying

2t^2-2=0

Solving for t

t=1\ ,t=-1

Only t=1 belongs to the valid interval 1\leqslant t\leqslant 15

Taking the second derivative

N''(t) = 20(2+\frac{2}{t^2})

Which is always positive, so t=1 is a minimum

(b)

N(1)=20(1^2-2ln1)+ 30

N(1)=50 is a minimum

(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15

(d)

N(15)=20(15^2-2ln15)+ 30

N(15)=4391.7 is a maximum

7 0
3 years ago
Q4c hint<br>6 people<br>3 people<br>4 eggs<br>: ? eggs​
Sati [7]

Answer: um what

Step-by-step explanation: Wa

4 0
3 years ago
Read 2 more answers
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