Answer:
= 3,126 m / s
Explanation:
In a crash exercise the moment is conserved, for this a system formed by all the bodies before and after the crash is defined, so that the forces involved have been internalized.
the car has a mass of m = 1.50 kg a speed of v1 = 4.758 m / s and the mass of the train is M = 3.60 kg and its speed v2 = 2.45 m / s
Before the crash
p₀ = m v₁₀ + M v₂₀
After the inelastic shock
= m 
+ M 
p₀ =
m v₀ + M v₂₀ = m + M
We cleared the end of the train
M = m (v₁₀ - v1f) + M v₂₀
Let's calculate
3.60 v2f = 1.50 (2.15-4.75) + 3.60 2.45
= (-3.9 + 8.82) /3.60
= 1.36 m / s
As we can see, this speed is lower than the speed of the car, so the two bodies are joined
set speed must be
m v₁₀ + M v₂₀ = (m + M)
= (m v₁₀ + M v₂₀) / (m + M)
= (1.50 4.75 + 3.60 2.45) /(1.50 + 3.60)
= 3,126 m / s
Answer:5.45X10^3m
Explanation:So use the formula,v= fλ
3X10^8=5.5X10^4λ what Im saying is divide both and u should get 5454.54m but do sig figs to get answer
The water molecules only oscillate up and down and not across the wave as water waves are transverse waves. Thus, the oscillations of the particles are perpendicular to the direction of wave propagation.
Explanation:
Given that,
Force constant of the spring, k = 120 N/m
Frequency of vibration, f = 6 Hz
Solution,
(a) Let T is the time period of the spring. The relation between the frequency and the time period is given by :
T = 0.167 s
(b) Let 
is the angular frequency. It is given by :
(c) The relation between angular frequency and the spring constant is given by :
m = 0.084 kg
or m = 84 grams
Therefore, it is the required solution.
