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4vir4ik [10]
3 years ago
12

The diagram below shows a wave with its wavelength indicated in red.

Physics
2 answers:
Shtirlitz [24]3 years ago
8 0

Answer:

answer is D.it will decrease

AlexFokin [52]3 years ago
7 0

Answer:

D. It will decrease

Explanation: Study island ;)

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A spring, when compressed 0.20 m from the equilibrium position, stores 24 J. What is the value of the spring constant
Delvig [45]

Given that:

spring compressed ( x) = 0.2 m

                        Work (W) = 24 J

 determine , spring constant (x)=?

               We know hat ,

                      Work   (W) = (1/2). k.x²

                                   24 = 1/2 ( k × 0.2²)

                                     48 = k × 0.2²

                                      <em> k = 1200 N/m</em>

3 0
4 years ago
A 3-kg object is attached to a spring and moving in simple harmonic motion. Its angular frequency is 20 rads/sec. When the mass-
Trava [24]

Answer:19.5 J

Explanation:

Given

mass of block=3 kg

angular frequency=20 rad/sec

spring constant k=\omega _n^2m=1200 N/m

we know total energy remain conserved

E_T at x=0.1 m

E_T=E_P+E_K

Where E_K=kinetic energy

E_P=potential Energy

E_P=\frac{1}{2}kx^2

E_P=600\times 0.01=6 J

E_K=\frac{1}{2}mv^2

E_K=\frac{1}{2}\times 3\times 3^2=13.5 J

E_T=13.5+6=19.5 J

When mass reaches amplitude its velocity becomes zero

there is only potential energy which is equal to Total energy

E_T=E_P=19.5 J

7 0
3 years ago
Two boxes on opposite ends of a massless board that is 3.0 m long. The board is supported in the middle by a fulcrum. The box on
rosijanka [135]

Answer:

b. 1.1 m

Explanation:

It is given that the total distance between the masses is equal to the length of the board, which is 3 m. Therefore,

s_{1} + s_{2} = 3\ m\\\\s_{2} = 3\ m - s_{1}\ --------- eqn(1)

where,

s₁ = distance of fulcrum from left mass

s₂ = distance of fulcrum from right mass

In order to achieve balance, the torque due to both masses must be equal:

T_{1} = T_{2}\\m_{1}s_{1} = m_{2}s_{2}\\(25\ kg)(s_{1}) = (15\ kg)(s_{2})\\\\\frac{15\ kg}{25\ kg}(s_{2}) = s_{1}\\\\using\ eqn(1):\\(0.6)(3\ m - s_{1}) = s_{1}\\1.8\ m = 1.6\ s_{1}\\s_{1} = \frac{1.8\ m}{1.6}

s₁ = 1.1 m

Hence, the correct option is:

<u>b. 1.1 m</u>

4 0
3 years ago
the earth has a radius of 6.38×10^16 meter and turns around once on its axis in 24 hour.what is the radial acceleration of perso
Scrat [10]

337493603.8m/s²

Explanation:

Radius of the earth = 6.38 x 10¹⁶m

time = 24hr (86400s)

Unknown:

Centripetal acceleration = ?

Solution:

The centripetal acceleration is directed inward to keep the body from falling off the surface of the earth.

     centripetal acceleration  = \frac{v^{2} }{r}

  where v is the velocity and r is the radius

   also;

            v  = wr

  where w is the angular velocity

substituting in the equation for centripetal acceleration gives;

                 

          a = w²r

 also w = \frac{2 x pi}{T}

      therefore;

                 a = \frac{4 \pi  ^{2} r }{T^{2} }

 a = \frac{ 4 x 3.142^{2}  x 6.38 x 10^{16} }{86400^{2} }

 a = 337493603.8m/s²

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

5 0
4 years ago
Calculate the change in entropy that occurs in the system when 3.10 mole of isopropyl alcohol (C3H8O) melts at its melting point
ozzi

Answer:

3.10 mole of C3H8O change in entropy is 89.54 J/K

Explanation:

Given data

mole = 3.10 moles

temperature = -89.5∘C = -89 + 273 = 183.5 K

ΔH∘fus = 5.37 kJ/mol =  5.3 ×10^3 J/mol

to find out

change in entropy

solution

we know change in entropy is ΔH∘fus / melting point

put these value so we get change in entropy that is

change in entropy 5.3 ×10^3 / 183.5

change in entropy is 28.88 J/mol-K

so we say 1 mole of C3H8O change in entropy is 28.88 J/mol-K

and for the  3.10 mole of C3H8O change in entropy is 3.10 ×28.88  J/K

3.10 mole of C3H8O change in entropy is 89.54 J/K

4 0
3 years ago
Read 2 more answers
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