Question

X^2+y^2 +4x−6y+9=0 what is the center and the radius

Answer 1

Answer: Center (-2,3), radius 2

Step-by-step explanation: Subtract 9 from both sides, then complete the square for the x and y variables & add to both sides: $x^2+4x+4+y^2-6y+9=-9+4+9$ $= (x+2)^2+(y-3)^2=4$. The center of this circle in the form $(x-a)^2+(y-b)^2=r^2$ is (a,b) with radius r. a=-2, b=3, r=$\sqrt{4}$=2