Answer:
Step-by-step explanation:
What this question is asking of you is what is the greatest common divisor of 12 and 15. Or, what is the biggest number that divides both 12 and 15.
in order to find this we have to split each number into it's prime components.
for 12 they are 2,2 and 3 (
2
⋅
2
⋅
3
=
12
)
and for 15 they are 3 and 5 (
3
⋅
5
=
15
)
Out of those two groups (2,2,3) and (3,5) the only thing in common is 3, so 3 is the greatest common divisor. That tells us that the greatest number of groups that can exist and have the same number of girls and the same number of boys for each group is 3.
Now to find out how many girls and boys there are going to be in each group we divide the totals by 3, so:
12
3
=
4
girls per group, and
15
3
=
5
boys per group.
(just as a thought exercise, if there were 16 boys, the divisors would have been (2,2,3) and (2,2,2,2), leaving us with 4 groups [
2
⋅
2
] of 3 girls [12/4] and 4 boys [16/4] )
Answer:

Step-by-step explanation:





It'll be 4^2+ 3^2 then the answer you get you take the square root of it which will give you the hypotenuse.
Your answer would be 5 because square root of 25 is 5
If u want the formula it's a^2+b^=c^2
C is the hypotenuse and a and b is the lengths
The diagram in the question is a cylinder.
;The volume of a cylinder is given by;
Volume = πr²h
;Where π=3.14
r⇒radius of the base of the cylinder and
h ⇒ height of the cylinder.
∴Volume = 3.14×5²×3
=235.5 ft³
To the nearest cubic = 236 ft³
Answer:
- <u>No, he can get an output of 0 with the second machine (function B) but he cannot get an output of 0 with the first machine (function A).</u>
Explanation
The way each machine works is given by the expression (function) inside it.
<u>1) </u><em><u>Function A</u></em>
To get an output of 0 with the function y = x² + 3, you must solve the equation x² + 3 = 0.
Since x² is zero or positive for any real number, x² + 3 will never be less than 3 (the minimum value of x² + 3 is 3). So, it is not possible to get an output of 0 with the first machine.
<u>2) </u><em><u>Function B</u></em>
Solve 
So, he can get an output of 0 by using x = 4.