The answer is Hx = ½ Wsin θ cos θ
The explanation for this is:
Analyzing the torques on the bar, with the hinge at the axis of rotation, the formula would be: ∑T = LT – (L/2 sin θ) W = 0
So, T = 1/2 W sin θ. Analyzing the force on the bar, we have: ∑fx = Hx – T cos θ = 0Then put T into the equation, we get:∑T = LT – (L/2 sin θ) W = 0
Answer:
M∠DEC equals 123º.
Step-by-step explanation:
The sum of a triangle's three angles always equal 180º. The exterior angle, x, equals the two non-adjacent interior angles.
180 - {(x - 45)+(x - 12)} = m∠DEC
m∠DEC + x = 180
<u>(x - 45) + (x - 12) = x</u>
Solving for x:
(x - 45) + (x - 12) = x
x - 45 + x - 12 = x Remove parenthesis
2x - 57 = x Combine like terms
2x = x + 57 Add 57 to both sides
<u>x = 57</u><u> Subtract x from both sides</u>
Finding m∠D:
x - 45 = ?
<u>57 - 45 = </u><u>12º </u>
Finding m∠C:
x - 12 = ?
<u>57 - 12 = </u><u>45º </u>
<em>** </em><em>(Checking x: 12 + 45 = 57) </em><em>**</em>
<em>Finding </em>m∠DEC:
AC is a straight line, and because straight lines are equivalent to 180º, we subtract 57 from 180:
180 - 57 = 123º
Hope this helps,
❤<em>A.W.E.</em><u><em>S.W.A.N.</em></u>❤
5•3•x•x•x-5•x•x•y+5•x•y=
5x(3x^2-xy+y)
Hope this explanation helps
