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Lesechka [4]
3 years ago
8

HELP BRAINLIEST! I think its none of the above

Mathematics
2 answers:
mamaluj [8]3 years ago
7 0

Answer:

180 degrees

Explanation:

So if it was 90 degrees it would be the same thing just fliped. 180 means that it did a half a rotaion so it would be the mirrored of the original object. That is what we see the second figure is mirrored of the other. 90 degrees also would be different.

<h2><u>Answer: 180 degrees</u></h2>

dolphi86 [110]3 years ago
4 0

Answer:

It's 180 degree rotation.

Step-by-step explanation:

It's mirrored,  and a circle is 360 degrees, so half of that is 180. The triangle made a 180 turn to become a mirror reflection, therefore, it's 180 :) Hope this helps please mark brainliest <3

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A broker has calculated the expected values of two different financial instruments X and Y. Suppose that E(x)= $100, E(y)=$90 SD
Sveta_85 [38]

Expectation is linear, meaning

E(<em>a X</em> + <em>b Y</em>) = E(<em>a X</em>) + E(<em>b Y</em>)

= <em>a </em>E(<em>X</em>) + <em>b</em> E(<em>Y</em>)

If <em>X</em> = 1 and <em>Y</em> = 0, we see that the expectation of a constant, E(<em>a</em>), is equal to the constant, <em>a</em>.

Use this property to compute the expectations:

E(<em>X</em> + 10) = E(<em>X</em>) + E(10) = $110

E(5<em>Y</em>) = 5 E(<em>Y</em>) = $450

E(<em>X</em> + <em>Y</em>) = E(<em>X</em>) + E(<em>Y</em>) = $190

Variance has a similar property:

V(<em>a X</em> + <em>b Y</em>) = V(<em>a X</em>) + V(<em>b Y</em>) + Cov(<em>X</em>, <em>Y</em>)

= <em>a</em>^2<em> </em>V(<em>X</em>) + <em>b</em>^2 V(<em>Y</em>) + Cov(<em>X</em>, <em>Y</em>)

where "Cov" denotes covariance, defined by

E[(<em>X</em> - E(<em>X</em>))(<em>Y</em> - E(<em>Y</em>))] = E(<em>X Y</em>) - E(<em>X</em>) E(<em>Y</em>)

Without knowing the expectation of <em>X Y</em>, we can't determine the covariance and thus variance of the expression <em>a X</em> + <em>b Y</em>.

However, if <em>X</em> and <em>Y</em> are independent, then E(<em>X Y</em>) = E(<em>X</em>) E(<em>Y</em>), which makes the covariance vanish, so that

V(<em>a X</em> + <em>b Y</em>) = <em>a</em>^2<em> </em>V(<em>X</em>) + <em>b</em>^2 V(<em>Y</em>)

and this is the assumption we have to make to find the standard deviations (which is the square root of the variance).

Also, variance is defined as

V(<em>X</em>) = E[(<em>X</em> - E(<em>X</em>))^2] = E(<em>X</em>^2) - E(<em>X</em>)^2

and it follows from this that, if <em>X</em> is a constant, say <em>a</em>, then

V(<em>a</em>) = E(<em>a</em>^2) - E(<em>a</em>)^2 = <em>a</em>^2 - <em>a</em>^2 = 0

Use this property, and the assumption of independence, to compute the variances, and hence the standard deviations:

V(<em>X</em> + 10) = V(<em>X</em>)  ==>  SD(<em>X</em> + 10) = SD(<em>X</em>) = $90

V(5<em>Y</em>) = 5^2 V(<em>Y</em>) = 25 V(<em>Y</em>)  ==>  SD(5<em>Y</em>) = 5 SD(<em>Y</em>) = $40

V(<em>X</em> + <em>Y</em>) = V(<em>X</em>) + V(<em>Y</em>)  ==>  SD(<em>X</em> + <em>Y</em>) = √[SD(<em>X</em>)^2 + SD(<em>Y</em>)^2] = √8164 ≈ $90.35

8 0
4 years ago
If f(x)= x2 and g(x)= x + 6, find g(fo)).
eimsori [14]

Given:

The functions are

f(x)=x^2

g(x)=x+6

To find:

The value of g(f(0)).

Solution:

We have,

f(x)=x^2

Putting x=0, we get

f(0)=0^2

f(0)=0

Now,

g(f(0))=g(0)                [\because f(0)=0]

g(f(0))=0+6            [\because g(x)=x+6]

g(f(0))=6

Therefore, the value of g(f(0)) is 6 and the correct option is B.

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The function f(x) is to be graphed on a coordinate plane.
gregori [183]

Answer:

f(x) is going to be on the y axis or intercept and what number it is on the line is in quotes f(x)="6"+2(1.05)^x it would be at 6 on the y axis.

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2 years ago
TRP = QSP if T = 32, R=46, and P = 10x+6 find S
djverab [1.8K]

Answer:

C

Step-by-step explanation:

Since the triangles are congruent then corresponding angles are congruent.

∠ R and ∠ S are corresponding angles and congruent, thus

∠ S = ∠ R = 46° → C

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3 years ago
Assume that in a batch of 34 defective items there are 22 with major defects and 23 with minor defects.
astraxan [27]
There would be only one with both

7 0
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