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bixtya [17]
3 years ago
6

Kelly combines 6.54 ounces of strawberries with 6.09 ounces of blueberries to make fruit bowls.She pours the fruit equally into

three bowls, and has 1.68 ounces of fruit left over. How many ounces of fruit are in each bowl?
Mathematics
2 answers:
Talja [164]3 years ago
8 0

Answer:

3.65 ounces in each bowl

Step-by-step explanation:

Strawberry=6.54 ounces

Blueberry=6.09 ounces

If Kelly combines the two fruits to make fruits bowls

Then,

6.54 ounces of strawberry + 6.09 ounces of blueberry=12.63 ounces of fruits.

She pours the fruits equally in each bowl and has a leftover of 1.68 ounces.

Let quantity in each bowl = x

There are 3 bowls

Total quantity in three bowls=3x

Leftover=1.68

Total fruits = 12.63

We have the equation

3x+1.68=12.63

Subtract 1.68 from both sides

3x=12.63-1.68

3x= 10.95

Divide both sides by 3

x=10.95/3

x=3.65

Gwar [14]3 years ago
6 0

Answer:

3.65 ounces of fruit in each bowl

Step-by-step explanation:

If the combination was made with 6.54 ounces of strawberries and 6.09 ounces of blueberries, the total ounces of fruit used is 6.54 + 6.09 = 12.63 ounces.

The remaining after dividing in three bowls is 1.68, so the amount used is 12.63 - 1.68 = 10.95 ounces

If we divide this amount of fruit by three bowls, we have:

Amount of fruit per bowl = 10.95 / 3 = 3.65 ounces

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IgorLugansk [536]

Answer:

option D is true.

Step-by-step explanation:

The right-angled triangle is shown.

From the right-angled triangle,

The angle Ф = 60°

We know that the trigonometric ratio

tan Ф = opposite / adjacent

  • opposite = 4
  • adjacent = n

Thus,

tan 60 = 4 / n

√3 = 4/n

n = 4/√3

Thus,

n = 4/√3

  = (4 × √3) / (√3 × √3)

  = 4√3 / 3

Thus,

n  = 4√3 / 3

Using Pythagorean theorem

m = √n²+4²

m=\sqrt{\left(4\cdot \frac{\sqrt{3}}{3}\right)^2+4^2}

m=\sqrt{\frac{4^2}{3}+4^2}

m=\sqrt{\frac{64}{3}}

m=\frac{8}{\sqrt{3}}

m=\frac{8\sqrt{3}}{3}

Thus,

  • m=\frac{8\sqrt{3}}{3}
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Therefore, option D is true.

3 0
3 years ago
9. A ladder of length 23 feet leans against the side of a building. The angle of elevation of the ladder is 76. Find the distanc
irakobra [83]

<h3><u>Answer:</u></h3>

  • B) 22.32 feet

\quad\rule{300pt}{1pt}

<h3><u>Solution</u><u>:</u></h3>

we are given that , a ladder is placed against a side of building , which forms a right angled triangle . We wre given one side of a right angled triangle ( hypotenuse ) as 23 feet and the angle of elevation as 76 ° . We can find the Perpendicular distance from the top of the ladder go to the ground by using the trigonometric identity:

\qquad\quad\bull ~{\boxed{\bf{ Sin\theta =\dfrac{Perpendicular}{Hypotenuse}}} }~\bull

Here,

  • hypotenuse = 23 feet
  • \theta = 76°
  • Value of Sin\theta = 0.97
  • Perpendicular = ?

\quad\dashrightarrow\quad \sf { sin\theta =\dfrac{P}{H}}

\quad\dashrightarrow\quad \sf { sin76° =\dfrac{P}{23}}

\quad\dashrightarrow\quad \sf { 0.97=\dfrac{P}{23}}

\quad\dashrightarrow\quad \sf {P = 0.97 \times 23 }

\quad\dashrightarrow\quad \sf { P = 22.32}

‎ㅤ‎ㅤ‎ㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>distance </u><u>from </u><u>the </u><u>top </u><u>of </u><u>the </u><u>ladder </u><u>to </u><u>the </u><u>ground </u><u>is </u><u>2</u><u>2</u><u>.</u><u>3</u><u>2</u><u> </u><u>feet </u><u>!</u>

\rule{300pt}{2pt}

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aliina [53]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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