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melamori03 [73]
3 years ago
13

Suppose that there are two types of tickets to a show:Advance and same-day. Advance tickets cost $35 and same day tickets cost $

15. For one performance, there were 65 tickets sold in all, and the total amount paid for them was $1475. How many tickets of each type were sold?
Mathematics
1 answer:
sdas [7]3 years ago
5 0

Answer:    30 $15 tickets and 20 $35 tickets

Step-by-step explanation:

.X%2BY=50

2.15X%2B35Y=1150

From eq. 1,

15X%2B15Y=750

Subtract from eq. 2,

15X%2B35Y-15X-15Y=1150-750

20Y=400

Y=20

Then,

X%2B20=50

X=30

30 $15 tickets and 20 $35 ticket

Hope it helps

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vaieri [72.5K]

Answer:

ok so this might look confusing what you have to do is just ignore part of the problem in this one just ignore apples, blueberries and zucchini their not important

on saturday it looks like he sold 14 pounds on sunday 15 pounds

14+15=29

and each pound is 3.50 so

29*3.5= 29*3+29*0.5

29*3=87

29*0.5=14.5

87+14.5=101.5

c

Hope This Helps!!!

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