You can Draw a segment WY connecting the centers<span> of the </span>two circles<span>, and then draw a segment, WS, so that YS + SZ = YZ and WS ⊥ YZ).</span>
Answer:
Step-by-step explanation:
A. abject - 2. wretched
B. congenial - 6. friendly
C. deliberately - 7. thoughtfully
D. impetuous - 3. impulsive
E. misgiving - 4. doubt
F. perturbation - 5. disturbance
G. pervade - 8. permeate
H. transgress - 1. err
Hope this helps :)
<h3>
Answer: 8/25</h3>
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Explanation:
In a standard deck, there are 52 cards.
If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.
There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.
Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.
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The event space has A = 16 cards in it, while the sample space has B = 50 cards.
The probability we're after is A/B = 16/50 = 8/25
