Answer:
Check the explanation
Step-by-step explanation:
Let 
and 
be sample means of white and Jesse denotes are two random variables.
Given that both samples are having normally distributed.
Assume having with mean 
and having mean 
Also we have given the variance is constant
A)
We can test hypothesis as
For this problem
Test statistic is
Where
We have given all information for samples
By calculations we get
s=2.41
T=2.52
Here test statistic is having t-distribution with df=(10+7-2)=15
So p-value is P(t15>2.52)=0.012
Here significance level is 0.05
Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.
We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.
Please explain more to the question where do the numbers go
Answer:
The correct answer is 2.
Step-by-step explanation:
To find this, first identify the ordered pairs at those two points. They would be (3, -2) and (6, 4). Then use the slope formula with those two points to find the rate of change.
m(slope) = (y2 - y1)/(x2 - x1)
m = (4 - - 2)/(6 - 3)
m = 6/3
m = 2
Answer:a=3/4
b=3/4
Step-by-step explanation:
3a+5b=6
9a+7b=12
-3(3a+5b)=-3(6)
9a+7b=12
-9a-15b=-18
9a+7b=12
-8b=-6
b=3/4
3a+5(3/4)=6
3a+15/4=6
3a=9/4
a=3/4
Answer: she will have $2042.4 have in the account after 1 year.
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = $2000
r = 2.1% = 2.1/100 = 0.021
n = 12 because it was compounded 12 times in a year.
t = 1 year
Therefore,
A = 2000(1 + 0.021/12)^12 × 1
A = 2000(1 + 0.00175)^12
A = 2000(1.00175)^12
A = $2042.4
