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RideAnS [48]
3 years ago
7

Answer please. no explanation needed!

Mathematics
1 answer:
vazorg [7]3 years ago
8 0
I believe the answer is 2
You might be interested in
I can't figure out how to do (i + j) x (i x j)for vector calc
Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}

Then, solving the determinant

\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}

In our case,

\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}

Where we used the formula for AxB to calculate ixj.

Finally,

\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}

Thus, (i+j)x(ixj)=i-j

8 0
1 year ago
Please I need this before 12pm
luda_lava [24]

Answer:

The required formula is:

                                                          {\displaystyle \ a_{n}=a_{1}+(n-1)d}

Step-by-step explanation:

The total number of squares of the the first term = 4

The total number of squares of the the second term = 7

The total number of squares of the the third term = 10

so,

a_1=4

a_2=7

a_3=10

Finding the common difference d

d=a_3-a_2=10-7=3

d=a_2-a_1=7-4=3

As the common difference 'd' is same, it means the sequence is in arithmetic.

So

If the initial term of an arithmetic progression is {\displaystyle a_{1}} and the common difference of successive members is d, then the nth term of the sequence (a_n) is given by:

                         {\displaystyle \ a_{n}=a_{1}+(n-1)d}

Therefore, the required formula is:

                                                          {\displaystyle \ a_{n}=a_{1}+(n-1)d}

3 0
3 years ago
Cual es resultado de 8.5 × 10^4 - 3.0 × 10^3
Veronika [31]
Simplify 10^4 to 10000

8.5x10000-3.0x10^3

Simplify 8.5x*10000 to 85000x
85000x-3.0*10^3
Simplify 3.0x10^3 to 3*10^3
Answer 85000x-3*10^3
5 0
3 years ago
Make t the subject of the formula q=2-4t/t+3
stira [4]

Answer:

q. (3+t)=2-4t

q.3+q.t=2-4t

4t+q.t=2-3q

t (4+q)=2-3q

t=2-3q/4+q

Step-by-step explanation:

PLZZ MARK AS BRAINLIEST!!!!!

8 0
2 years ago
Which set is closed under subtractionWhich answer choice shows that the set of irrational numbers is not closed under addition
vovikov84 [41]

Answer:

(a) Set of rational numbers

(b) \pi + (-\pi) = 0

Step-by-step explanation:

Solving (a): Set that is closed under subtraction

The solution to this is rational numbers.

For a set of number to be closed under subtraction, the following condition must be true

a -b = c

Where

a, b, c are of the same set.

The above is only true for rational numbers.

e.g.

1 - 2 = -1

5 - 5 = 0

\frac{1}{2} - \frac{1}{4} = \frac{1}{2}

4 - 2 = 2

The operations and the result in the above samples are rational numbers.

Solving (b): Choice not close under addition[See attachment for options]

As stated in (a)

For a set of number to be closed under subtraction, the following condition must be true

a -b = c

Where

a, b, c are of the same set.

In the given options (a) to (d), only

\pi + (-\pi) = 0 is not close under addition because:

\pi is irrational while 0 is rational

<em>In other words, they belong to different set</em>

8 0
2 years ago
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