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Gwar [14]
3 years ago
11

Does this graph represent a function? Yes, no

Mathematics
1 answer:
Nadya [2.5K]3 years ago
3 0

Answer:

yes

Step-by-step explanation:

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Khan sold his cycle at loss of 8%.had He sold it for 240 more he would have gained 12%
denpristay [2]

Khan sold his cycle at loss of 8%.had He sold it for 240 more he would have gained 12%. Then cost price is $ 1200 and selling price is $ 1104

<h3><u>Solution:</u></h3>

Assume the cost price be "a"

So the selling price of cycle = a - 8% of a

\text { selling price }=a-\frac{8 a}{100}=\frac{23 a}{25}

Now according to given, had He sold it for 240 more he would have gained 12%

Selling price + 240 = cost price + 12% profit

\frac{23a}{25} + 240 = a + \frac{12a}{100}

\frac{23a + 6000}{25} = \frac{100a + 12a}{100}\\\\92a + 24000 = 112a\\\\20a = 24000\\\\a = 1200

So the cost price is $ 1200

Now the selling price = \frac{23a}{25} = \frac{23 \times 1200}{25} = 1104

So the selling price is $ 1104

7 0
3 years ago
Which expression is equivalent to 3√x^5?
Elanso [62]
∛x^5 y
= (x)^5/3 y^1/3

answer
B. second option

6 0
3 years ago
Help me please I beg please but please
stealth61 [152]

Answer:

9. \frac{1}{10} fraction.

10. \frac{3}{10} fraction.

Step-by-step explanation:

In the given table, we get, Andrea hiked \frac{2}{5} of the total trail, Jon hiked \frac{1}{2} of the total trail and Callie hiked \frac{4}{5} of the total trail.

9. Therefore, Jon hiked (\frac{1}{2} - \frac{2}{5}) = \frac{5 - 4}{10} = \frac{1}{10} fraction than Andrea hiked.

10. Therefore, Callie hiked (\frac{4}{5} - \frac{1}{2}) = \frac{8 - 5}{10} = \frac{3}{10} fraction than Jon hiked. (Answer)

4 0
3 years ago
Helppp please! ill give brainliest!
Ket [755]

Answer:

i dont know to be honest

Step-by-step explanation:

4 0
3 years ago
Help me to answer this question pl​s
attashe74 [19]

Problem 1

Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.

Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.

With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.

Refer to the diagram below.

=====================================================

Problem 2

I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.

In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.

8 0
2 years ago
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