Solution
The table below is the required sample space of the to fair die
From the above table
The sample space contain 36 outcomes
Event A: The sum is greater than 9
we will look at the table and count all the elements that are greater than 9
There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)
The probability for event A will be
P(A) = 1/6
Event B: The sum is an even number.
We will look at the table and count the number of elements that are even
There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)
The probability for event B will be
p(B) = 1/2
Answer:
5.74 so that would be the third option
Step-by-step explanation:
always remember to square root if not answer will be counted as incomplete or incorrect!
Answer: 0.2401
Step-by-step explanation:
The binomial distribution formula is given by :-
where P(x) is the probability of x successes out of n trials, p is the probability of success on a particular trial.
Given : The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately: p =0.7.
Number of trials : n= 4
Now, the required probability will be :
Thus, the probability that, in a randomly selected sample of four citizen-entities, all of them are of pension age =0.2401
10cm X 100 = 1000 is the answer mate
Answer:
why?
Step-by-step explanation:
