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inessss [21]
3 years ago
8

Complex ions with different ligands have different colors because the ligands: Group of answer choices are different colors affe

ct the energy levels of the lone-pair electrons on the metal have different energies for their bonding electrons affect the energy levels of the metal d orbitals have different energies for their lone-pair electrons
Chemistry
1 answer:
Gnesinka [82]3 years ago
8 0

Answer:

The correct answer is the second last statement, that is, it affects the energy levels of the metal d orbitals.

Explanation:

It is because of the d-d transition of electrons that the metal complexes exhibit color. When bonding of the ligands takes place with the transition metal ion, a repulsion results between the electrons in the d orbitals of the metal ion and the electrons found within the ligands. This increases the d orbitals' energy level.  

However, based on the alignment of the d orbitals in the space, all of the energies do not get elevated by the same level, it gets dissociate into two groups. This dissociation of the d-orbitals relies upon the ligand's strength. More amount of energy would be required to encourage an electron from the lower orbitals groups to the move towards the higher ones in case if the splitting is more.  

Greater energy is equivalent to shorter wavelengths in terms of the color of the light absorbed. The complex ions possessing different ligands show distinct kinds of colors as the energy levels of the d orbitals of the metal get affected by the ligands.  

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How many moles do you have in 37.3 g of Co(CrO4)3​
shutvik [7]

Answer:

0.0917 mol Co(CrO₄)₃

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

37.3 g Co(CrO₄)₃

<u>Step 2: Identify Conversions</u>

Molar Mass of Co - 58.93 g/mol

Molar Mass of Cr - 52.00 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Co(CrO₄)₃ - 58.93 + 3(52.00) + 12(16.00) = 406.93 g/mol

<u>Step 3: Convert</u>

<u />37.3 \ g \ Co(CrO_4)_3(\frac{1 \ mol \ Co(CrO_4)_3}{406.93 \ g \ Co(CrO_4)_3} ) = 0.091662 mol Co(CrO₄)₃

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.091662 mol Co(CrO₄)₃ ≈ 0.0917 mol Co(CrO₄)₃

8 0
3 years ago
Which of the following is an example of maintaining homeostasis? A. Learning B. Jumping C. Shivering D. Smiling
yawa3891 [41]

Answer:

Shivering.

Explanation:

Homeostasis is the bodies need to keep things at a normal. When you are cold you shiver to produce body heat and get back to normal  

5 0
3 years ago
Which is a characteristic of a decomposition reaction? Substance P replaces X in the compound XY. Substance XYZ breaks down into
Law Incorporation [45]

Substance P replaces X in the compound XY

this is the characteristic of decomposition reaction

6 0
3 years ago
A student weighed an empty graduated cylinder. It weighed 35.86 g. She then carefully added water to the graduated cylinder unti
Firdavs [7]

Question:

A student weighed an empty graduated cylinder. It weighed 35.86 g. She then carefully added water to the graduated cylinder until it reached the 7.5 mL mark. When she weighed the graduated cylinder again, this time with the 7.5 mL of water in it, it weighed 43.18 g. What was this student's experimental density of water?

Answer:

0.976 g/mL

Explanation:

Weight of empty cylinder = 35.86g

Volume of water = 7.5mL

Weight of cylinder + water = 43.18g

Experimental density = ?

Density of water = Mass of water / volume of water

Mass of water = (Weight of cylinder + water) - Weight of empty cylinder

Mass of water = 43.18 - 35.86 = 7.32g

Density = 7.32 / 7.5 = 0.976 g/mL

5 0
3 years ago
Which of these conjugate acid-base pairs will not function as a buffer?
miv72 [106K]

Answer:HNO₃ and NO³⁻ would not function as buffer

Explanation:

The buffer solution are usually prepared by using  any  weak acid (which would partially dissociate)  and mixing this weak acid with its own conjugate base or any weak base (which would partially dissociate) and mixing with  with its conjugate acid.

A buffer solution is a solution which resists change in pH of the solution.

Since nitric acid is a very strong acid and hence neither nitric acid HNO₃ or its conjugate base NO³⁻ anionb is suitable for the preparation of buffer solution.

HCO³⁻ is a weak  acid and hence it can form a buffer solution with its conjugate base CO₃²-. so they can be used to form buffer.

C₂H₅COOH is a weak acid and hence it can also form buffer solution with its conjugate base.

So only HNO₃and NO³⁻ would not be able to form buffer

So option a is the answer.

8 0
3 years ago
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