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Advocard [28]
3 years ago
8

What other objects are often arranged by their properties

Chemistry
1 answer:
blagie [28]3 years ago
8 0

Answer:

Metaloids and metals.

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. A large quantity of very dilute aqueous HCl solution is neutralized by the addition of the stoichiometric amount of a 10-mol-%
ad-work [718]

Answer:

Make the question more clear for me

Explanation:

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Where is the atmosephere the most dence
likoan [24]
The Earths Surface, it’s also known as the troposphere also dense* lol
8 0
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Read 2 more answers
What is the correct name of this compound?
Reika [66]

Answer:

7. 3–ethyl–6 –methyldecane

8. 5–ethyl–2,2–dimethyl–4–propyl–4 –heptene

Explanation:

It is important to note that when naming organic compounds having two or more different substituent groups, we simply name them alphabetically.

The name of the compound given in the question above can be written as follow:

7. Obtaining the name of the compound.

Compound contains:

I. Decane.

II. 3–ethyl.

III. 6 –methyl.

Naming alphabetically, we have

3–ethyl–6 –methyldecane

8. Obtaining the name of the compound.

Compound contains:

I. 2,2–dimethyl.

II. 4–propyl.

III. 4 –heptene.

IV. 5–ethyl.

Naming alphabetically, we have

5–ethyl–2,2–dimethyl–4–propyl–4 –heptene

8 0
3 years ago
Using the idea that reactions occur as a result of collisions between particles, explain why reaction rates depend on the temper
PIT_PIT [208]

Increasing temperatures in a reaction increases the kinetic energy of the reactant molecules. This causes them to move fast and hence collide with a higher frequency. The higher the rate of collision between the molecules, the faster the reaction.

6 0
3 years ago
Using the following equation for the combustion of octane calculate the heat associated with the formation of 100.0 g of carbon
natali 33 [55]

Answer:

The right solution is "-602.69 KJ heat".

Explanation:

According to the question,

The 100.0 g of carbon dioxide:

= \frac{100.0 \ g}{114.33\  g/mole}

= 0.8747 \ moles

We know that 16 moles of CO_2 formation associates with -11018 kJ of heat, then

0.8747 moles CO_2 formation associates with,

= -\frac{0.8747}{16}\times 11018 \ KJ \ of \ heat

= -0.0547\times 11018

= -602.69 \ KJ \ heat

8 0
3 years ago
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