Answer:
The net Electric field at the mid point is 289.19 N/C
Given:
Q = + 71 nC =
Q' = + 42 nC =
Separation distance, d = 1.9 m
Solution:
To find the magnitude of electric field at the mid point,
Electric field at the mid-point due to charge Q is given by:
Now,
Electric field at the mid-point due to charge Q' is given by:
Now,
The net Electric field is given by:
Answer:
μ = 0.350
Explanation:
For the person to able to move the box, the force exerted by the person on the box must equal the force exerted by the box:
In this case, force can be calculated as a product of mass (m) by the acceleration of gravity (g) and the coefficient of static friction (μ):
Therefore, for the person to be able to push the box horizontally, the coefficient of static friction between the box and the floor should not be higher than 0.350.
You are dealing with pulleys?
can be done with addition of the two equations to eliminate T.
+
=
we can cancel m₁ by dividing both sides by it, assuming mass is not zero
a₂ = 6.125 m/s² ( do significant digits if you need to)
Explanation:
It is given that,
Length of wire, l = 0.53 m
Current, I = 0.2 A
(1.) Approximate formula:
We need to find the magnitude of the magnetic field made by the current at a location 2.0 cm from the wire, r = 2 cm = 0.02 m
The formula for magnetic field at some distance from the wire is given by :
B = 0.000002 T
(2) Exact formula:
B = 0.00000199 T
or
B = 0.000002 T
Hence, this is the required solution.
Answer:
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Explanation:
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