Answer:
a) the distance between her and the wall is 13 m
b) the period of her up-and-down motion is 6.5 s
Explanation:
Given the data in the question;
wavelength λ = 26 m
velocity v = 4.0 m/s
a) How far from the wall is she?
Now, The first antinode is formed at a distance λ/2 from the wall, since the separation distance between the person and wall is;
x = λ/2
we substitute
x = 26 m / 2
x = 13 m
Therefore, the distance between her and the wall is 13 m
b) What is the period of her up-and-down motion?
we know that the relationship between frequency, wavelength and wave speed is;
v = fλ
hence, f = v/λ
we also know that frequency is expressed as the reciprocal of the time period;
f = 1/T
Hence
1/T = v/λ
solve for T
Tv = λ
T = λ/v
we substitute
T = 26 m / 4 m/s
T = 6.5 s
Therefore, the period of her up-and-down motion is 6.5 s
To solve this problem we will use the linear motion kinematic equations, for which the change of speed squared with the acceleration and the change of position. The acceleration in this case will be the same given by gravity, so our values would be given as,

Through the aforementioned formula we will have to

The particulate part of the rest, so the final speed would be



Now from Newton's second law we know that

Here,
m = mass
a = acceleration, which can also be written as a function of velocity and time, then

Replacing we have that,


Therefore the force that the water exert on the man is 1386.62
Answer:
15
Explanation:
displacement = initial position - final position
Answer:
To summarize, <em><u>Jane's star</u></em> has a <em><u>red</u></em> light and <em><u>is traveling towards</u></em> the <em><u>Earth</u></em> while <em><u>John's star </u></em>has a <em><u>blue</u></em> light and <em><u>is traveling away</u></em> from the <em><u>Earth</u></em>. This is a <em><u>prime example</u></em> of the <em><u>Doppler Effect</u></em> in <em><u>motion</u></em>. The stars <em><u>look different </u></em>because <em><u>they are traveling in different directions.</u></em>