Answer:
change of momentum does not depend on the mass of the cars, as the force and time are the same all vehicles have the same change of momentum
Explanation:
Let's look for the speed of the car
F = m a
a = F / m
We use kinematics to find lips
v = v₀ + a t
v = v₀ + (F / m) t
The moment is defined by
p = m v
The moment change
Δp = m v - m v₀
Let's replace the speeds in this equation
Δp = m (v₀
+ F / m t) - m v₀
Δp = m v₀ + F t - m v₀
Δp = F t
We see that the change of momentum does not depend on the mass of the cars, as the force and time are the same all vehicles have the same change of momentum
Answer: F = 1391 N
Explanation:
The information given to you are:
Mass M = 1300 kg
Acceleration a = 1.07 m/s^2
The magnitude of the force striking the building will be
F = ma
Where
F = force
Substitute mass M and acceleration a into the formula
F = 1300 × 1.07
F = 1391 N
Therefore, the wrecking ball strikes the building with a force of 1391 N
The tension in the cord is 14.7 N and the force of pull of the cord is 14.7 N, assuming the block is stationary.
<h3>
What is the tension in the cord?</h3>
The tension in the cord is calculated as follows;
T = ma + mg
where;
- a is the acceleration of the block
- g is acceleration due to gravity
- m is mass of the block
T = m(a + g)
T = 1.5(a + 9.8)
T = 1.5a + 14.7
Thus, the tension in the cord is (1.5a + 14.7) N.
If the block is at rest, the tension is 14.7 N.
<h3>Force of the force</h3>
The force with which the cord pulls is equal to the tension in the cord
F = T = m(a + g)
F = (1.5a + 14.7) N
If the block is stationary, a = 0, the tension and force of pull of the cord = 14.7 N.
Thus, the tension in the cord is 14.7 N and the force of pull of the cord is 14.7 N, assuming the block is stationary.
Learn more about tension here: brainly.com/question/187404
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