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Agata [3.3K]
3 years ago
13

A women weighs 857 N. What is her mass?

Physics
2 answers:
klemol [59]3 years ago
7 0

Answer:

women based on height usually should way about 200 pounds which included muscle.

Explanation:

djyliett [7]3 years ago
4 0
Right now, the woman’s weight is in Newtons. Weight is always measured in Newtons (N), and mass will always be measured in kilograms (kg), so we need to convert her weight in Newtons into mass in kilograms. The equation for weight is Fg = mg. Force of gravity equals mass times gravity.
Force of gravity is another way of saying weight. We are given her weight, and we also know that gravity is 9.8m/s^2; therefore, you can set up your algebraic equation like this: 857 = m x 9.8. Now, you have to divide 857 by 9.8 to get mass by itself. 857/9.8 is approximately 87.4489 kilograms.

So your answer is 87.4489 kg!

The full answer is 87.44897959, but in physics, we usually just like to use the four numbers after the decimal place.
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Points A [at (2, 3) m] and B [at (5, 7) m] are in a region where the electric field is uniform and given by E = (4i+3j)N/C. What
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Answer:

- 144 V

Explanation:

A = (2, 3) m = 2 i + 3 j

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Displacement vector = AB = B - A = (3 i + 4 j) m

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V = - E . AB

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V = - (12 + 12) = - 144 V

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Many devices have been invented to accurately measure temperature. It all started with the establishment of a temperature scale. This scale transformed the measurement of temperature into meaningful numbers.

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Later in that century, around 1743, Anders Celsius (1701-1744) invented the Celsius scale. Using the same anchor points, he determined the freezing temperature for water to be 0 degree and the boiling temperature 100 degrees. The Celsius scale is known as a Universal System Unit. It is used throughout science and in most countries.


There is a limit to how cold something can be. The Kelvin scale is designed to go to zero at this minimum temperature. The relationships between the different temperature scales are:



oK = 273.15 + oC        oC = (5/9)*(oF-32)        oF = (9/5)*oC+32


 oF oC oK

Water boils 212 100 373

Room Temperature 72 23 296

Water Freezes 32 0 273

Absolute Zero -460 -273 0

At a temperature of Absolute Zero there is no motion and no heat. Absolute zero is where all atomic and molecular motion stops and is the lowest temperature possible. Absolute Zero occurs at 0 degrees Kelvin or -273.15 degrees Celsius or at -460 degrees Fahrenheit. All objects emit thermal energy or heat unless they have a temperature of absolute zero.


If we want to understand what temperature means on the molecular level, we should remember that temperature is the average energy of the molecules that composes a substance. The atoms and molecules in a substance do not always travel at the same speed. This means that there is a range of energy (the energy of motion) among the molecules. In a gas, for example, the molecules are traveling in random directions at a variety of speeds - some are fast and some are slow. Sometimes these molecules collide with each other. When this happens the higher speed molecule transfers some of its energy to the slower molecule causing the slower molecule to speed up and the faster molecule to slow down. If more energy is put into the system, the average speed of the molecules will increase and more thermal energy or heat will be produced. So, higher temperatures mean a substance has higher average molecular motion. We do not feel or detect a bunch of different temperatures for each molecule which has a different speed. What we measure as the temperature is always related to the average speed of the molecules in a system

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Explanation:

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An 80- quarterback jumps straight up in the air right before throwing a 0.43- football horizontally at 15 . How fast will he be
lord [1]

Answer:

a)

the quarterback will be moving back at speed of 0.080625 m/s

b)

the distance moved horizontally by the quarterback is 0.0241875 m or 2.41875 cm

Explanation:

Given the data in the question;

a)

How fast will he be moving backward just after releasing the ball?

using conservation of momentum;

m₁v₁ = m₂v₂

v₂ = m₁v₁ / m₂

where m₁ is initial mass ( 0.43 kg )

m₂ is the final mass ( 80 kg )

v₁ is the initial velocity  ( 15 m/s )

v₂ is the final velocity

so we substitute

v₂ = ( 0.43 × 15 ) / 80

v₂ = 6.45 / 80

v₂ = 0.080625 m/s

Therefore, the quarterback will be moving back at speed of 0.080625 m/s

b) Suppose that the quarterback takes 0.30 to return to the ground after throwing the ball. How far d will he move horizontally, assuming his speed is constant?

we make use of the relation between time, distance and speed;

s = d/t

d = st

where s is the speed ( 0.080625 m/s )

t is time ( 0.30 s )

so we substitute

d = 0.080625 × 0.30

d = 0.0241875 m or 2.41875 cm

Therefore, the distance moved horizontally by the quarterback is 0.0241875 m or 2.41875 cm

5 0
3 years ago
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