A :-) F = ma
Given - m = 95 kg
a = 2.2 m/s^2
Solution -
F = ma
F = 95 x 2.2
F = 209
.:. The force is 209 N
a) since force = mass * acceleration
f= 900 * 0 (because constant speed = 0 acceleration)
similarly b) f = 0
Answer:
A shorter than the original source and in the researcher's words
Explanation:
The summary is an abridged version of the original source and in the researcher's own very words.
Summaries gives an over-arching perspective and excludes implicit details from a given text.
A summary should not be detailed and must avoid overt illustrations. They must capture the true essence of piece leaving out flowery details.
A summary should be lesser in length than the original piece. Any third party reader should immediately be able to grab the details of the original piece from the summary.
To solve this problem we will apply the concept related to the magnetic dipole moment that is defined as the product between the current and the object area. In our case we have the radius so we will get the area, which would be



Once the area is obtained, it is possible to calculate the magnetic dipole moment considering the previously given definition:



Therefore the magnetic dipole moment is 