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Agata [3.3K]
3 years ago
13

A women weighs 857 N. What is her mass?

Physics
2 answers:
klemol [59]3 years ago
7 0

Answer:

women based on height usually should way about 200 pounds which included muscle.

Explanation:

djyliett [7]3 years ago
4 0
Right now, the woman’s weight is in Newtons. Weight is always measured in Newtons (N), and mass will always be measured in kilograms (kg), so we need to convert her weight in Newtons into mass in kilograms. The equation for weight is Fg = mg. Force of gravity equals mass times gravity.
Force of gravity is another way of saying weight. We are given her weight, and we also know that gravity is 9.8m/s^2; therefore, you can set up your algebraic equation like this: 857 = m x 9.8. Now, you have to divide 857 by 9.8 to get mass by itself. 857/9.8 is approximately 87.4489 kilograms.

So your answer is 87.4489 kg!

The full answer is 87.44897959, but in physics, we usually just like to use the four numbers after the decimal place.
You might be interested in
When temperature and pressure are applied to sedimentary and igneous rock?
spin [16.1K]
Answer:

Igneous rock

Explanation:

Igneous rocks are formed through the cooling and solidification of magma. It undergoes changes in temperature and pressure that causes it to cool, solidify, and crystallize.
6 0
3 years ago
Newton's second law of motion can also be described as...
Irina-Kira [14]

Answer


B. F=ma



Explanation

The Newton's laws of motion tries to explain the how bodies behave and the energy changes when theys are in motion. For the 3 of them to hold, the bodies must be moving in a straight line and with constant velocity.

The second one states that, "the change of momentum of a moving body is directly proportional to the force producing it and it takes place to the direction of force."

From the choices given, the appropriate answer is B. F=ma

6 0
3 years ago
Two charged objects have a repulsive force of .80 N. If the charge of one of the objects is doubled, then what is the new force?
sveticcg [70]
The new force would be 1.6 N.
Since the charges multiply as variables (q1)x(q2), then it would simply be double (q1)x(q2), or 1.6.
6 0
3 years ago
How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 4.00
klio [65]

Explanation:

Let us assume that the separation of plate be equal to d and the area of plates is 9 \times 10^{-4} m^{2}. As the capacitance of capacitor is given as follows.

            C = \frac{\epsilon_{o}A}{d}

It is known that the dielectric strength of air is as follows.

               E = 3 \times 10^{6} V/m

Expression for maximum potential difference is that the capacitor can with stand is as follows.

                       dV = E × d

And, maximum charge that can be placed on the capacitor is as follows.

               Q = CV

                   = \frac{\epsilon_{o} A}{d} \times E \times d

                   = \epsilon_{o}AE

                   = 8.85 \times 10^{-12} \times 3 \times 10^{6} \times 4 \times 10^{-4}

                   = 1.062 \times 10^{-8} C

or,                = 10.62 nC

Thus, we can conclude that charge on capacitor is 10.62 nC.

5 0
3 years ago
7. A 1.0 kg metal head of a geology hammer strikes a solid rock with a velocity of 5.0 m/s. Assuming all the energy is retained
marta [7]

The increase in temperature of the metal hammer is 0.028 ⁰C.

The given parameters:

  • <em>mass of the metal hammer, m = 1.0 kg</em>
  • <em>speed of the hammer, v = 5.0 m/s</em>
  • <em>specific heat capacity of iron, 450 J/kg⁰C</em>

The increase in temperature of the metal hammer is calculated as follows;

Q = K.E\\\\mc \Delta T = \frac{1}{2}  mv^2\\\\\Delta T = \frac{v^2}{2 c}

where;

<em>c is the </em><em>specific heat capacity</em><em> of the metal hammer</em>

<em />

Assuming the metal hammer is iron, c = 450 J/kg⁰C

\Delta T = \frac{5^2}{2 \times 450} \\\\\Delta T = 0.028 \ ^0C

Thus, the increase in temperature of the metal hammer is 0.028 ⁰C.

Learn more about heat capacity here: brainly.com/question/16559442

8 0
2 years ago
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