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3 years ago

A women weighs 857 N. What is her mass?

Physics

2 answers:

klemol [59]3 years ago

7 0

Answer:

women based on height usually should way about 200 pounds which included muscle.

Explanation:

djyliett [7]3 years ago

4 0

Right now, the woman’s weight is in Newtons. Weight is always measured in Newtons (N), and mass will always be measured in kilograms (kg), so we need to convert her weight in Newtons into mass in kilograms. The equation for weight is Fg = mg. Force of gravity equals mass times gravity.
Force of gravity is another way of saying weight. We are given her weight, and we also know that gravity is 9.8m/s^2; therefore, you can set up your algebraic equation like this: 857 = m x 9.8. Now, you have to divide 857 by 9.8 to get mass by itself. 857/9.8 is approximately 87.4489 kilograms.

So your answer is 87.4489 kg!

The full answer is 87.44897959, but in physics, we usually just like to use the four numbers after the decimal place.

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Three Carnot engines operate between the following temperature limits.

Kipish [7]

Answer:c>a>b

Explanation:

Given

All the engine extracts same amount of heat(Q) from High-temperature reservoir

For a) 400 and 500 K

$\eta _{engine}=1-\frac{T_L}{T_H}$

$\eta _{engine}=\frac{work\ supplied}{heat\ supplied}$

$1-\frac{400}{500}=\frac{W_a}{Q}$

$W_a=\frac{Q}{5}$

For b)500 K and 600K

$1-\frac{500}{600}=\frac{W_b}{Q}$

$W-b=\frac{Q}{6}$

For c) 400 K and 600 K

$1-\frac{400}{600}=\frac{W_c}{Q}$

$W_c=\frac{2Q}{3}$

So c will give the highest amount of work

c>a>b

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3 years ago

Which of the following is the best example of an object in free fall?

SashulF [63]

The answer is D because theres nothing stopping that person from falling

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Juli2301 [7.4K]

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2 years ago

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4. A meter has a resistance of 100 Ω and gives a full scale deflection when it carries a current of 25 μA. (a) What resistor, Rx

frez [133]

Answer:

A=50mΩ

B≅50mΩ

Explanation:

A) To answer this question we have to use the Current Divider Rule. that rule says:

$Ix=.\frac{Req}{Rx} *Itotal$ (1)

Itotal represents the new maximun current, 50mA, Ix is the current going through the 100 ohms resistor, and Req. is the equivalent resitor.

We now have a set of two resistor in parallel, so:

$Req.=\frac{1}{\frac{1}{R1}+\frac{1}{R2} }$ (2)

where R1 is the resitor we have to calculate, and R2 is the 100 ohms resistor (25 uA).

substituting and rearranging (2)

$Req.=\frac{ 100*R1}{R1+100}$ (3)

Now substituting (3) in (1).

$25*10^{-6} =\frac{\frac{ 100*R1}{R1+100}}{100} *50*10^{-3}$

solving this, The value of R1 is: 50mΩ

This value of R1 will guaranty that the ammeter full reflection willl be at 50mA.

Given that R2 (100ohm) it too much bigger than 50mΩ, the equivalent resistor will tend to 50mΩ

If you substitude this values on (2) Req. will be 49.97 mΩ.

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shusha [124]

Hello,

Here is your answer:

The proper answer to this question will be option A "An accelerating electric point charge (electron) emits electromagnetic waves." That's because electromagnetic waves are formed by motion of electrically charged particles (electrons)!

Your answer is A!

If you need anymore help feel free to ask me!

Hope this helps!

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