Answer:
C - 3 (negative 64 divided by 8) + 25 =1
Step-by-step explanation:
I used to hate fractions. But in time, you learn to love them. This is because there's a big difference between fractions and decimals, even though when you divide the actual fraction it comes out to a decimal. Decimals go on and on sometimes, and it would be impossible to write out all those numbers, especially when taking a timed test, for example. Fractions, in this case, would be much more useful (as long as you know how to use them to your advantage). Fractions are basically all those decimal numbers wrapped up into a single, simple division. It makes the outcome of your answer much more accurate than if you estimate every decimal you get throughout a math problem. The more you estimate throughout the problem-solving process, the less accurate your final answer will be. Hence why teachers will usually tell you to estimate when you're putting down the final answer. Fractions are complex at times, so it may be easier to use them in decimal form for certain situations (especially if the decimal form is short and sweet). A world without fractions will result in many, many inaccurate situations involving mathematical knowledge.
9514 1404 393
Answer:
4a. ∠V≅∠Y
4b. TU ≅ WX
5. No; no applicable postulate
6. see below
Step-by-step explanation:
<h3>4.</h3>
a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...
∠V≅∠Y
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b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...
TU ≅ WX
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<h3>5.</h3>
The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)
"No, we cannot prove they are congruent because none of the five postulates or theorems can be used."
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<h3>6.</h3>
The first statement/reason is always the list of "given" statements.
1. ∠A≅∠D, AC≅DC . . . . given
2. . . . . vertical angles are congruent
3. . . . . ASA postulate
4. . . . . CPCTC
Answer:
Perimeter of the parallelogram = 26.64 units
Step-by-step explanation:
The perimeter of parallelogram = 2(a + b)
Here a = KJ = 7 units.
b = HK
We need to find the HK using the distance formula.
Distance formula = 
H = (-4, 3) and k = (-2, -3)
Now plug in x1 = -4, y1 =3, x2 = -2, y2 = -3 in the distance formula
HK = 
= 
= 
= 
HK = b = 6.32 units
Now plug in a = 7 and b = 6.32 in the perimeter formula, we get
Perimeter = 2(7 + 6.32)
= 2(13.32)
= 26.64 units
Thank you.
Answer:
A. (2 × 6) + (3 × 8) + 6²
72 sq. inches.
B. 9 in. by 8 in.
Step-by-step explanation:
The white shape has dimensions of 2 in. by 6 in. and the green shape is a square.
So, the dimension of the green shape is 6 in. by 6 in.
Therefore, the length of the blue shape is (6 + 2) = 8 in.
Now, given that the area of the blue shape is 24 sq. in.
So, the width of the blue shape is 
in.
Now, if we consider the total figure, then area of the entire figure = area of the white shape + area of the green shape + area of the blue shape.
= (2 × 6) + (3 × 8) + 6² (Answer)
= 12 + 24 + 36
= 72 sq, inches. (Answer)
Now, the length of the entire figure is (6 + 3) = 9 in. and width of the entire figure is (2 + 6) = 8 in.
Therefore, the dimensions of the entire figure will be 9 in. by 8 in. (Answer)
