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Butoxors [25]
3 years ago
11

You wish to package a spherical globe inside a cubical box . The diameter of the globe is 30 centimeters . How much empty space

is there inside the rectangular prism ( i.e. how much space is there between the prism and the globe ) ? Hint Volume Rectangular Prism is L x W x H
Mathematics
1 answer:
Aneli [31]3 years ago
5 0

Answer:

<h2>The empty inside the box is 12,870 cubic centimeters, approximately.</h2>

Step-by-step explanation:

Givens

  • The diameter of the globe (sphere) is 30 centimeters,
  • The box must has dimensions 30x30.

We need to find each volume to subtract them.

V_{box}=(30cm)^{3}=  27,000 \ cm^{3}

V_{sphere}=\frac{4}{3} \pi (15cm)^{3} \approx 14,130 \cm^{3}

The difference betweem the box and the sphere is

\Delta V=27,000 - 14,130 = 12,870 \ cm^{3}

Therefore, the empty inside the box is 12,870 cubic centimeters, approximately.

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Glven: -7x &lt; -21. Choose the solution set.​
SVEN [57.7K]

Answer:

x > 3

Step-by-step explanation:

-7x < -21

Divide each side by -7, remembering to flip the inequality

-7x/-7 > -21/-7

x > 3

7 0
3 years ago
Read 2 more answers
The net weight in pounds of a packaged chemical herbicide is uniform for 49.62 &lt; x &lt; 50.04 pounds.
k0ka [10]

Answer:

a) E(X)=\frac{50.64+49.62}{2}=50.13 pounds

b) Var(X)= \frac{(b-a)^2}{12} =\frac{(50.04-49.62)^2}{12}=0.0147

c) P(X

But we see that the distribution is defined ust between 49.62 and 50.04

And in order to find this we can use the CDF (Cumulative distribution function) given by:

F(X) =\frac{x-a}{b-a}

And if we replace we got:

P(X

And makes sense since all the values are between 49.62 and 50.04

Step-by-step explanation:

For this case we define the random variable X ="net weigth in pounds of a packaged chemical herbicide" and the distribution for X is given by:

X \sim U(a= 49.62, b=50.04)

Part a

For the uniform distribution the expected value is given by E(X) =\frac{a+b}{2} where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

E(X)=\frac{50.64+49.62}{2}=50.13 pounds

Part b

The variance for an uniform distribution is given by:

Var(X)= \frac{(b-a)^2}{12}

And if we replace we got:

Var(X)= \frac{(b-a)^2}{12} =\frac{(50.04-49.62)^2}{12}=0.0147

Part c

For this case we want to find this probability:

P(X

But we see that the distribution is defined ust between 49.62 and 50.04

And in order to find this we can use the CDF (Cumulative distribution function) given by:

F(X) =\frac{x-a}{b-a}

And if we replace we got:

P(X

And makes sense since all the values are between 49.62 and 50.04

6 0
4 years ago
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Answer:

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Step-by-step explanation:

B will be  <u> 2 </u>  out of   <u>4 + 3 + 2</u>   =    2/9 of the total

            2/9 * 450 000 = 100 000

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2 years ago
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4 years ago
Someone please help me
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Answer:

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