Answer:
The probability of selecting randomly 6 packets such that the first 4 contain cocaine and 2 not is 0.3522.
Step-by-step explanation:
Probabilities of selecting 4 packets with the ilegal substance:
= 
Combinassions possible= 1365
Probabilities of selecting 2 packets with white powder:
= 
Combinations possible= 10
Probabilities of selecting 6 packets from the totality of them:
= 
Combinations possible= 38760
The probability of picking 4 with the substance and 2 with only white powder is:
= 0.3522
I hope this answer helps you.
Answer:
y=1/8
Step-by-step explanation:
Answer:
Yes.
Step-by-step explanation:
Because
6*4 =24
and 4*0 = 0,
24+0=24
have a nice day!!!
Answer:
Question 2 is $500 and Question 3 is 5
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form: (3,2)
Equation form:
x = 3
y = 2