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Nat2105 [25]
3 years ago
15

PLEASE HELP!! • Which of these are equivalent to -11/4 ? Choose ALL that apply.

Mathematics
1 answer:
weeeeeb [17]3 years ago
5 0

Answer: -11 divided by 4 , 11 divided by -4 , -11/4 , 11/-4 ,

Step-by-step explanation:

I got it right on iready

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The price of a wallet is $31.95 and the sales tax is 7.5%.
Musya8 [376]

Answer:

34.35

Step-by-step explanation:

8 0
3 years ago
What is the square root
shusha [124]

Answer:

Step-by-step explanation:

Trying to factor as a Difference of Squares :

1.1      Factoring:  r2-96

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 96 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Equation at the end of step  1  :

 r2 - 96  = 0

Step  2  :

Solving a Single Variable Equation :

2.1      Solve  :    r2-96 = 0

Add  96  to both sides of the equation :

                     r2 = 96

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:  

                     r  =  ± √ 96  

Can  √ 96 be simplified ?

Yes!   The prime factorization of  96   is

  2•2•2•2•2•3

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 96   =  √ 2•2•2•2•2•3   =2•2•√ 6   =

               ±  4 • √ 6

The equation has two real solutions  

These solutions are  r = 4 • ± √6 = ± 9.7980  

Two solutions were found :

                  r = 4 • ± √6 = ± 9.7980

Processing ends successfully

4 0
3 years ago
Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15
Digiron [165]

\huge \boxed{\mathfrak{Question} \downarrow}

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\left. \begin{array}  { l  }  { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.

  • To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2x-5y=-13, \: 3x+4y=15

  • Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

2x-5y=-13

  • Add 5y to both sides of the equation.

2x=5y-13

  • Divide both sides by 2.

x=\frac{1}{2}\left(5y-13\right)  \\

  • Multiply \frac{1}{2}\\ times 5y - 13.

x=\frac{5}{2}y-\frac{13}{2}  \\

  • Substitute \frac{5y-13}{2}\\ for x in the other equation, 3x + 4y = 15.

3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15  \\

  • Multiply 3 times \frac{5y-13}{2}\\.

\frac{15}{2}y-\frac{39}{2}+4y=15  \\

  • Add \frac{15y}{2} \\ to 4y.

\frac{23}{2}y-\frac{39}{2}=15  \\

  • Add \frac{39}{2}\\ to both sides of the equation.

\frac{23}{2}y=\frac{69}{2}  \\

  • Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{ \underline{ \sf \: y=3 }}

  • Substitute 3 for y in x=\frac{5}{2}y-\frac{13}{2}\\. Because the resulting equation contains only one variable, you can solve for x directly.

x=\frac{5}{2}\times 3-\frac{13}{2}  \\

  • Multiply 5/2 times 3.

x=\frac{15-13}{2}  \\

  • Add -\frac{13}{2}\\ to \frac{15}{2}\\ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

\large\underline{ \underline{ \sf \: x=1 }}

  • The system is now solved. The value of x & y will be 1 & 3 respectively.

\huge\boxed{  \boxed{\bf \: x=1, \: y=3 }}

8 0
2 years ago
Are the following lines are parallel ,perpendicular or neither
Art [367]

Answer: parallel

they just are <3

3 0
3 years ago
A gardener buys a rake and a pair of gloves for each of the 12 volunteers in the gardening club. Each pair of gloves
matrenka [14]

Let unit cost of one rake be : r

Given : Total number of volunteers = 12

Given : Each pair of gloves cost $8.00

⇒   Cost of 12 pair of gloves for 12 volunteers = (12 × 8) = $96

Given : The gardener spends a total of $300 on both rakes and gloves

⇒   Cost of 12 rakes + Cost of 12 pair of gloves = $300

⇒   12r + 96 = 300

⇒   12r = 204

⇒   r = 17

<u>Answer</u> : Cost of one rake is $17

4 0
3 years ago
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