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2 years ago

Solve e^x = e^2x + 5.

Mathematics

1 answer:

Aliun [14]2 years ago

5 0

Answer:

x= -0.782588

Alternative form= 5/1-e2

Step-by-step explanation:

You might be interested in

Every week hector works 20 hours and earns $210.00 he earns a constant amount of money per hour white a equation that can be use

erik [133]

Answer:

to find out how much hector earns a hour we can do

Step-by-step explanation:

210 ÷ 20

I think you missed some writing it doesn't say the whole question. so I'm not really sure^^

8 0

3 years ago

When purchasing bulk orders of batteries, a toy manufacturer uses this acceptance sampling plan: Randomly select and test 49 b

Brilliant_brown [7]

Answer:

Step-by-step explanation:

Given that A shipment contains 6000 batteries, and 1% of them do not meet specifications.

Sample size =49

If x is the number of batteries not meeting specifications then

x is binomial with n =49 and p = 0.01

Because i) each toy is independent of the other

ii) There are only two outcomes

Probability whole shipment is accepted = Prob (X≤3)

=0.9885

Hence almost all shipments would be accepted.

4 0

3 years ago

Suppose that x and y are both differentiable functions of t and are related by the given equation. Use implicit differentiation

stepan [7]

Answer:

Let z = f(x, y) where f(x, y) =0 then the implicit function is

$\frac{dy}{dx} =$ $\frac{-δ f/ δ x }{δ f/δ y }$

Example:- $\frac{dy}{dx} = \frac{-(y+2x)}{(x+2y)}$

Step-by-step explanation:

Partial differentiation:-

Let Z = f(x ,y) be a function of two variables x and y. Then

$\lim_{x \to 0} \frac{f(x+dx,y)-f(x,y)}{dx}$ Exists , is said to be partial derivative or Partial differentiational co-efficient of Z or f(x, y)with respective to x.

It is denoted by δ z / δ x or δ f / δ x

Let Z = f(x ,y) be a function of two variables x and y. Then

$\lim_{x \to 0} \frac{f(x,y+dy)-f(x,y)}{dy}$ Exists , is said to be partial derivative or Partial differentiational co-efficient of Z or f(x, y)with respective to y

It is denoted by δ z / δ y or δ f / δ y

Implicit function:-

Let z = f(x, y) where f(x, y) =0 then the implicit function is

$\frac{dy}{dx} =$ $\frac{-δ f/ δ x }{δ f/δ y }$

The total differential co-efficient

d z = δ z/δ x + $\frac{dy}{dx}$ δ z/δ y

Implicit differentiation process

differentiate both sides of the equation with respective to 'x'

move all d y/dx terms to the left side, and all other terms to the right side

factor out d y / dx from the left side
Solve for d y/dx , by dividing

Example : $x^2 + x y +y^2 =1$

solution:-

differentiate both sides of the equation with respective to 'x'

$2x + x \frac{dy}{dx} + y (1) + 2y\frac{dy}{dx} = 0$

move all d y/dx terms to the left side, and all other terms to the right side

$x \frac{dy}{dx} + 2y\frac{dy}{dx} = - (y+2x)$

Taking common d y/dx

$\frac{dy}{dx} (x+2y) = -(y+2x)$

$\frac{dy}{dx} = \frac{-(y+2x)}{(x+2y)}$

7 0

3 years ago

The Insurance Institute reports that the mean amount of life insurance per household in the US is $110,000. This follows a norma

nata0808 [166]

Answer:

a) $\sigma_{\bar X} = \frac{\sigma}{\sqrt{n}}= \frac{40000}{\sqrt{50}}= 5656.85$

b) Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

c) $P( \bar X >112000) = P(Z>\frac{112000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>0.354)$

And we can use the complement rule and we got:

$P(Z>0.354) = 1-P(Z$

d) $P( \bar X >100000) = P(Z>\frac{100000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>-1.768)$

And we can use the complement rule and we got:

$P(Z>-1.768) = 1-P(Z$

e) $P(100000< \bar X$

And we can use the complement rule and we got:

$P(-1.768$

Step-by-step explanation:

a. If we select a random sample of 50 households, what is the standard error of the mean?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the amount of life insurance of a population, and for this case we know the distribution for X is given by:

$X \sim N(110000,40000)$