Calculate the ph of a 0.10 m solution of hydrazine, n2h4. kb for hydrazine is 1.3×10−6.
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Answer: x = 20
We know opposite angles are equivalent so we can set both of these expressions equal to each other to solve for x.
3x + 50 = 6x - 10
50 = 3x - 10 (subtract 3x from both sides)
60 = 3x (add 10 to both sides)
20 = x (divide both sides by 3)
We know opposite angles are equivalent so we can set both of these expressions equal to each other to solve for x.
3x + 50 = 6x - 10
50 = 3x - 10 (subtract 3x from both sides)
60 = 3x (add 10 to both sides)
20 = x (divide both sides by 3)
