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ikadub [295]
3 years ago
6

Calculate the ph of a 0.10 m solution of hydrazine, n2h4. kb for hydrazine is 1.3×10−6.

Mathematics
1 answer:
horrorfan [7]3 years ago
7 0
N2H4 + H2O = N2H5(+) + OH(-) 

<span>Kb = 1.3 E-06 = [N2H5(+)][OH(-)] / [N2H4] = [OH(-)]^2 / 0.1 </span>

<span>Thus [OH(-)] = 0.000361 </span>

<span>pOH = -log[OH(-)] = 3.44 </span>

<span>pH = 14 - pOH = 10.6

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
</span>
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There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl
Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0
4 years ago
The speed of the current in a river is 6mph. A ferry operator who works that part of the river is looking to buy a new boat for
Nezavi [6.7K]
Hello,
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4 0
3 years ago
A zookeeper weighed an African elephant to be 9x10^3 pounds and an African lion to be 4x10^2 pounds. How many times greater is t
maria [59]
Answer:  22.5 .  The weight of the elephant is "22.5 times greater" than                              the weight of the lion.
_________________________________________________________
Explanation:
_________________________________________________________

(weight of lion) * (x) = (eight of the elephant)  ;  Solve for "x" .
_____________________________________________________
   → Divide each side of the equation by "(weight of lion)" ;
  to isolate "x" on one side of the equation ; and to solve for "x" ;
_________________________________________________________
    
   → (weight of lion)*(x) / (weight of lion) = (weight of the elephant) /
                                                           (weight of lion) ;
________________________________________________________
     →  x  = (weight of the elephant) / (weight of lion) ;
__________________________________________________________
     →  Plug in our "given values" ; and solve for "x" ;
__________________________________________________________
     →  x = (<span>9*10</span>³) / (4*10²) =  (9*10⁽³⁻²⁾) / 4  =  (9*10¹) / 4  ;
__________________________________________________________  
     →  x =  90 /4 = 25/2  = 22.5 ; which is our answer.
__________________________________________________________
4 0
3 years ago
The perimeter of a triangle is 50 mm. The lengths of 2 of the sides are 13.5 mm and 14.5 mm. Find the missing length.
Naddik [55]
The missing side length should be 22. Add 13.5 to 14.5 and you should get 28. Subtract 28 from the total perimeter (50) to get 22.
5 0
3 years ago
If cp=rs 400, loss=10% find sp<br>​
Shalnov [3]

Answer:

cp = rs 400

loss = 10%

Then SP = 400 - 10% of 400

= 400 - 40

= 360

Therefore SP = Rs. 360

6 0
2 years ago
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