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3 years ago

Calculate the ph of a 0.10 m solution of hydrazine, n2h4. kb for hydrazine is 1.3×10−6.

1 answer:

7 0

N2H4 + H2O = N2H5(+) + OH(-)

<span>Kb = 1.3 E-06 = [N2H5(+)][OH(-)] / [N2H4] = [OH(-)]^2 / 0.1 </span>

<span>Thus [OH(-)] = 0.000361 </span>

<span>pOH = -log[OH(-)] = 3.44 </span>

<span>pH = 14 - pOH = 10.6

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