The answer is d.subx=0/y=0
<span>Find the wind speed and the plane's airspeed.
:
Let s = speed of the plane in still air
Let w = speed of the wind
then
(s-w) = plane speed against the wind
and
(s+w) = plane speed with the wind
:
Change 3 3/8 hrs to 3.375 hrs
:
The trips there and back are equal distance, (1890 mi) write two distance equations
dist = time * speed
:
3.375(s-w) = 1890
3.0(s + w) = 1890
:
It is convenient that we can simplify both these equations:
divide the 1st by 3.375
divide the 2nd by 3
resulting in two simple equations that can be used for elimination of w
s - w = 560
s + w = 630
----------------adding eliminates w, find s
2s = 1190
s =
s = 595 mph is the plane speed in still air
Find w
595 + w = 630
w = 630 - 595
w = 35 mph is the wind spee</span>
The answer would be C.
If you do -5.5 + 2.5 over 6.1 - 3.1 it would be -3 over 3 which is equal to -1.
You could also do -2.5 + 5.5 over 3.1 - 6.1. It would be 3 over -3 which is also equal to -1.
Answer:
22 feet
Step-by-step explanation:
Area of circle = pi(r²)
the square root of 121 is 11, so r = 11
d = 2r
d = 22
Answer:
34.8 x 10 to the power of 0.
Step-by-step explanation:
hope this helps
