Let b and s be the velocity of the boat and stream respectively....
3(b-s)=27
b-s=9
b=9+s we will use this in the second equation....
2(b+s)=30
b+s=15, now use b found above in this to get:
9+s+s=15
2s+9=15
2s=6
s=3, and since from earlier b-s=9, b=9+s so
b=12
So the speed of the boat is 12mph and the stream is 3 mph
When the triangle is a right triangle, you can use the Pythagorean theorem. The formula would be
c^2 = a^2 + b^2
If a = 21 and c=29, thus
b^2 = c^2 - a^2
b^2 = 29^2 - 21^2
b^2 = 400
b = square root (400)
b = 20 units.
Thus, the answer is <span>D) B = 400</span>
Answer:
Step-by-step explanation:
First write the problem out as a fraction.
Next see if there is a GCF
4:1,2,4
16:1,2,4,8,16
Finally divide the numerator and denomenator by the GCF
Answer:
A = 11 i believe
Step-by-step explanation:
