Answer with explanation:
When a Dice is rolled once , total possible Outcome ={1,2,3,4,5,6}=6
When a dice is rolled twice, total possible outcome={(1,1),(2,2),(3,3),(4,4),(5,5),(6,6),(1,2),(1`,3),(1,4),(1,5),(1,6),(2,1),(3,1),(4,1),(5,1),(6,1),(2,3),(2,4),(2,5),(2,6),(3,2),(4,2),(5,2),(6,2),(3,4),(3,5),(3,6),(4,3),(5,3),(6,3),(4,5),(4,6),(5,6),(5,4),(6,4),(6,5)} =6²=36
When a coin is tossed , total possible Outcome ={H,T}=2
So, total number of Possible outcomes
=If we join one H along 36 Possible outcome when dice is tossed twice +If we join one T with 36 Possible outcome when dice is tossed twice
= 36 + 36
= 72 Outcome
