Answer:
60 m
Explanation:
Arthur and Betty will be walking for the same amount of time t
Speed of Arthur = 3 m/s
Speed of Betty = 2 m/s
Distance = Speed × time
Distance covered by Arthur = 3t
Distance covered by Betty = 2t
Distance that Arthur and Betty will cover will be 100 m
3t+2t = 100
⇒5t = 100
⇒t = 100/5
⇒t = 20 s
So, Arthur and Betty will be walking for 20 seconds
Spot is by Arthur's side and keeps running in between them until they meet. So, Spot will be running for 20 seconds and the displacement covered will be the distance covered by Arthur which is
3t = 3×20 = 60m
Displacement is the shortest distance between two points so, Spot's displacement will be 60 m
Answer: B
R = 2 ohms
Explanation:
When resistors are connected in parallel, the equivalent resistance R will be less than the least resistance.
1/R = 1/R1 + 1/R2 + 1/R3 + 1/R4 + 1/R5
Since the 5 resistors are 10 ohms each, substitute them in to the formula
1/R = 1/10 + 1/10 +1/10 + 1/10 + 1/10
The LCM = 10
1/R = 5/10
Reciprocate both sides
R = 10/5 = 2 ohms
The correct option is B
Answer:
R = 4Ω
Explanation:
If we have two resistors with resistances R1 and R2 in series the total resistance is R = R1 + R2
If the resistances are in parallel, the total resistance is given by:
1/R = 1/R1 + 1/R2.
First, we have a resistor with R1 = 1.5Ω
This resistor is connected in series with a parallel part (let's find the resistance of this parallel part), in one branch we have two resistors in series with resistances:
R2 = 8Ω and R3 = 4Ω
Because these are in series, the resistance of that branch is:
R = 8Ω + 4Ω = 12Ω
In the other branch, we have a single resistor of R4 = 4Ω
The resistance of the parallel part is:
1/R = 1/12Ω + 1/4Ω = 1/12Ω + 3/12Ω = 4/12Ω = 1/3Ω
1/R = 1/3Ω
R = 3Ω
Then we have a resistor (the first one, R1 = 1.5Ω) in series with a resistor of 3Ω.
Then the total resistance is:
R = 1Ω + 3Ω = 4Ω
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