Answer:
At 10°F change in temperature
Mass flowrate = 1.01 kg/s = 2.227 lbm/s
Volumetric flowrate = 1010 m³/s = 35667.8 ft³/s
At 20°F change in temperature
Mass flowrate = 0.505 kg/s = 1.113 lbm/s
Volumetric flowrate = 505 m³/s = 17833.9 ft³/s
Explanation:
80000 btu/hr = 23445.7 W
P = ṁc(ΔT)
ṁ = MASS flowrate
c = specific heat capacity of water = 4182 J/kg.K,
ΔT = change in temperature = 10°F
To convert, a change of 18°F is equal to a change of 10°C
A change of 10°F = 10×10/18 = 5.556°C = 5.556K
P = ṁc(ΔT)
23445.7 = ṁ(4182 × 5.556)
ṁ = 23445.7/(4182 × 5.556)
ṁ = 1.01 kg/s = 2.227 lbm/s
In volumetric flow rate, Q = density × mass flowrate = 1000 × 1.01 = 1010 m³/s = 35667.8 ft³/s
For a change of 20°F,
ΔT = change in temperature = 20°F
To convert, a change of 18°F is equal to a change of 10°C
A change of 20°F = 20×10/18 = 11.1111°C = 11.111K
P = ṁc(ΔT)
23445.7 = ṁ(4182 × 11.111)
ṁ = 23445.7/(4182 × 11.111)
ṁ = 0.505 kg/s = 1.113 lbm/s
In volumetric flow rate, Q = density × mass flowrate = 1000 × 0.505 = 505 m³/s = 17833.9 ft³/s
Hope this Helps!!!
