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Gennadij [26K]
3 years ago
15

Describe the initial horizontal and vertical velocity of a horizontally launched projectile on Earth, as well as what happens to

each velocity as the object moves along its trajectory, and why.
Physics
1 answer:
Jobisdone [24]3 years ago
5 0

Answer:

Explained below

Explanation:

To explain this, let's consider a tennis ball being launched from the top of a very high building.

Now, if the tennis ball is launched horizontally without any upward angle but with an initial velocity of 10 m/s. In this motion, If there is no gravity, the tennis ball would continue in motion at that same speed of 10 m/s in the horizontal direction. However, in reality, gravity causes the tennis ball to accelerate downwards at a rate of 9.8 m/s for every second. This implies that the vertical velocity component is changing at the rate of 9.8 m/s every second.

Thus, after 1 second, horizontal velocity component will remain 10 m/s and vertical component will be 9.8 m/s × 1 = 9.8 m/s downwards.

Also, after 2 seconds, the vertical velocity component will remain 10 m/s, however the vertical component will now be 9.8 × 2 = 19.6 m/s downwards.

Same procedure is repeated as t increases by 1 second.

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True / False: All elements will burn a particular color, sometimes with hints of other colors showing.
marshall27 [118]

Answer:

true

Explanation:

it all depends on the elements that are burning for the different types of colors.

6 0
3 years ago
A circular loop (radius of 20 cm) is in a uniform magnetic field of 0.15 T. What angle(s) between the normal to the plane of the
Wittaler [7]

Answer:

The angle other than 90 degrees would result in magnetic flux of non zero magnitude.

Explanation:

The magnetic flux through a given closed area is equal to \underset{B}{\rightarrow}.\underset{A}{\rightarrow}.

    Where \underset{B}{\rightarrow} is the magnitude of magnetic flux through loop .

                \underset{A}{\rightarrow} is the area vector of the given loop .

      We know that \underset{B}{\rightarrow}.\underset{A}{\rightarrow} = \left | A \right |\left | B \right |\cos \theta,

 Where \theta is the angle made by magnetic field with area vector.

   Area vector of a closed loop is always normal to the plane of the loop .

So from above equation we can deduce that

                  \theta = \cos^{-1}\frac{\phi }{\left | A \right |\left | B \right |}      

      \phi is the magnitude of magnetic flux which is non zero when \theta not equal to 90 degrees.

8 0
3 years ago
What is the distance a jet travels over a 4.25 hour flight if it is traveling 14.75 km/s?
Phoenix [80]

Well, there's no jet that can travel at that speed ... 14.75 km/s is like 33,000 miles per hour !  But I'll just take the numbers that are there, and work it out just the way the question says.

Distance = (14.75 km/s) x (4.25 hours) x (3,600 sec/hour)

Distance = (14.75 x 4.25 x 3,600) (km-hr-sec/sec-hr)

<em>Distance = 225,675 km</em>  (a little more than half-way to the Moon)

7 0
4 years ago
a large cargo trucks needs to cross a bridge the truck is 30m long, and 3.2 wide, the cargo exerts a force of 54,000 N the bridg
otez555 [7]

Answer:

It isn't safe for the truck to cross the bridge because the pressure exerted by the truck on the bridge is greater than the maximum tolerable pressure for the bridge, 562.5 Pa > 450 Pa.

Explanation:

Pressure is expressed in Force/Area.

So, for the truck, force exerted = 54000 N

Area covered = 30 × 3.2 = 96 m²

Pressure exerted by the truck = 54000/96 = 562.5 Pa

The pressure exerted by the truck on the bridge is greater than the maximum tolerable pressure for the bridge, 562.5 > 450, hence, it isn't safe for the truck to cross the bridge.

5 0
4 years ago
A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10
sashaice [31]

Answer:

Time interval;Δt ≈ 37 seconds

Explanation:

We are given;

Angular deceleration;α = -1.6 rad/s²

Initial angular velocity;ω_i = 59 rad/s

Final angular velocity;ω_f = 0 rad/s

Now, the formula to calculate the acceleration would be gotten from;

α = Change in angular velocity/time interval

Thus; α = Δω/Δt = (ω_f - ω_i)/Δt

So, α = (ω_f - ω_i)/Δt

Making Δt the subject, we have;

Δt = (ω_f - ω_i)/α

Plugging in the relevant values to obtain;

Δt = (0 - 59)/(-1.6)

Δt = -59/-1.6

Δt = 36.875 seconds ≈ 37 seconds

6 0
4 years ago
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