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Tju [1.3M]
3 years ago
11

(Please someone help me it’s urgent) I need to pass this

Chemistry
1 answer:
Mrac [35]3 years ago
3 0

The superscript 3 in 4pº tell that there are 3 electrons in this orbital

<h3>Further explanation</h3>

In an atom there are levels of energy in the shell and sub shell

This energy level is expressed in the form of electron configurations.  

There are 4 sub-shells in the shell of an atom, namely s, p, d, and f. The maximum number of electrons for each sub-shell is  

• s: 2 electrons  

• p: 6 electrons  

• d: 10 electrons and  

• f: 14 electrons  

Charging electrons in the sub-shell uses the following sequence:  

<em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  </em>

Arsenic is an element with the symbol As, which has an atomic number of 33 and a mass number of 75

Electron configuration of As : [Ar] 3d¹⁰4s²4p³

<em>Each superscript shows the number of electrons that occupy each orbital </em>

For the p orbital there are a maximum of 6 electrons, while the 4p³ orbital shows that there are 3 electrons in this orbital

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Use the periodic table to determine the electron configuration for Ca and Pm in noble-gas notation Ca: [Ar]4s2 [Ar]4s1 [Ar]3s2 [
sveta [45]
Answer:

1) Ca: [Ar]4s²
2) Pm: [Xe]6s²4f⁵

Explanation:

1) Ca:

Its atomic number is 20. So it has 20 protons and 20 electrons.

Since it is in the row (period) 4 the noble gas before it is Ar, and the electron configuration is that of Argon whose atomic number is 18.

So, you have two more electrons (20 - 18 = 2) to distribute.

Those two electrons go the the orbital 4s.

Finally, the electron configuration is [Ar] 4s².

2) Pm

The atomic number of Pm is 61, so it has 61 protons and 61 electrons.

Pm is in the row (period) 6. So, the noble gas before Pm is Xe.

The atomic number of Xe is 54.

Therefore, you have to distribute 61 - 54 = 7 electrons on the orbitals 6s and 4f.

The resultant distribution for Pm is: [Xe]6s² 4f⁵.
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What is the oxidation state of each element in the compound CaSO4? Include + or - in your answers as appropriate.
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Answer:- Ca = +2, S = +6 and O = -2

Solution:- There are certain rules for oxidation numbers. As per the rule, oxidation number of alkaline earth metals in their compounds is +2.

Oxidation number of oxygen in it's compounds is -2(except peroxides) and the sum of oxidation numbers of all the elements of a neutral compound is zero.

Since, Ca is +2 and O is -2, the oxidation number of S could easily be calculated for the given compound as:

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Hence. the oxidation number of Ca is +2, O is -2 and S is +6.


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