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Soloha48 [4]
2 years ago
7

WHAT IS 225/100 IN DECIMALS AND PERCENTAGES

Mathematics
2 answers:
Alex_Xolod [135]2 years ago
7 0

Answer:

2.25 and 225%

Step-by-step explanation:

Ivahew [28]2 years ago
3 0
That would be 225% and 2.25 I really hope this helps!!
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Find the missing denominator or numerator of 1/2 = /4
Jet001 [13]
Simply cross-multiply about,

\bf \cfrac{1}{2}=\cfrac{x}{4}\implies 4\cdot 1=2\cdot x\implies 4=2x\implies \cfrac{4}{2}=x\implies 2=x
6 0
3 years ago
Read 2 more answers
Write the equation of the line that passes through the given points in slope intercept form
shepuryov [24]

Answer:

y=3x

Step-by-step explanation:

To put this in slope intercept form, let’s first find the slope

To find slope, use the equation Y2-Y1/X2-X1

When we do this, we get 0-6/0-2

This simplifies out into -6/-2 which is 3

So our slope is 3. Our equation becomes y=3x+b

Now, we find our b

We don’t have to do any solving for this, since we have the point 0,0 listed for us, it goes through the origin and that is our y-intercept or b

So our final equation is y=3x

Hope this helps and have a good day!

5 0
2 years ago
Read 2 more answers
On your wedding day you leave for the church 34 minutes before the ceremony is to begin, which should be plenty of time since th
Schach [20]

Answer:

Average speed   is 37.35 mi/h

Step-by-step explanation:

given data

leave =  34 minutes before

church distance =  12.0 miles

average speed first 17 minutes =  5.0 mi/h

solution

so we find Total distance travel in first 17 minutes = speed × time

Total distance travel in first 17 minutes = 5 × \frac{17}{60}

Total distance travel in first 17 minutes = 1.416 mi

and

Distance Remaining = 12 - 1.416 = 10.584 mi

Time Remaining = 34 - 17 min = 17 min

so

remaining distance Average speed  = \frac{distance}{time}

Average speed  = \frac{10.584}{\frac{17}{60}}

Average speed   is 37.35 mi/h

3 0
3 years ago
An investigator thinks that people under the age of forty have vocabularies that are different than those of people over sixty y
Kay [80]

Answer:

t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

p_v =2*P(t_{60}  

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

Step-by-step explanation:

Information given

\bar X_{1}=14 represent the mean for sample 1 (younger)

\bar X_{2}=20 represent the mean for sample 2 (older)  

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=31 sample size for the group 2  

n_{2}=31 sample size for the group 2  

t would represent the statistic

System of hypothesis

We want to test if  that people under the age of forty have vocabularies that are different than those of people over sixty years of age, the system of hypothesis are:

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

The statistic is given by:

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=31+31-2=60  

Replacing the info given we got:

t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

p_v =2*P(t_{60}  

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

6 0
3 years ago
E^(i.π)+2^(-2+3-1)+21899921030
Anna007 [38]

Answer:

21899921030

Step-by-step explanation:

e^(i.π) = -1

2^(-2+3-1) = 2^0 = 1

Therefor

-1 + 1 + 21899921030 = 21899921030

5 0
2 years ago
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