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Anna71 [15]
3 years ago
6

In a pedigree, when a circle of square is halfway shaded, is it

Chemistry
1 answer:
exis [7]3 years ago
6 0
Ummm I think it is C. ( not sure)
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What happens to an oxidizing agent during a redox reaction?
Gnoma [55]

Answer:

An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. ... A reducing agent is oxidized, because it loses electrons in the redox reaction.

Explanation:

An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. ... A reducing agent is oxidized, because it loses electrons in the redox reaction.

4 0
3 years ago
Why does water flow decrease in your shower when someone flushes the toilet ​
Rashid [163]

Answer:

A toilet requires a large amount of cold water to flush. So, when the toilet flushes while you're in the shower, it's stealing from your shower's cold water supply. When the pressure-balancing valve senses the drop in cold water pressure, it responds by restricting the hot water pressure.

6 0
3 years ago
Read 2 more answers
Hc1 is the formula for .
PIT_PIT [208]

Answer:

HCl is the formula for Hydrochloric acid

Explanation:

  • Chemical formula is a formula of a compound showing the symbols of elements present in the compound.
  • Chemical formula also shows the number of atoms of each element present in a compound.
  • HCl is the chemical formula of hydrochloric acid. From this formula we can tell that hydrochloric acid is made up of hydrogen and chlorine elements.
  • The formula also shows that HCl contains 1 hydrogen atom and 1 chlorine atom.
5 0
3 years ago
Which of the following is an example of anaerobic respiration?
Andrews [41]
Respiring while swimming underwater
Because anaerobic respiration means respiration with no oxygen, and there is no oxygen underwater
8 0
4 years ago
The value of the solubility product constant for Ag2CO3 is 8.5 × 10‒12 and that of Ag2CrO4 is 1.1 × 10‒12. From this data, what
Lena [83]

Answer:

B) 7.7

Explanation:

For the reaction    Ag2CO3(s) + CrO42‒(aq) → Ag2CrO4(s) + CO32‒(aq)

Kc = (CO₃²⁻) / (CrO₄²⁻)

and the Ksp given are

Ag₂CO₃    ⇒  2 Ag⁺(aq) + CO₃²⁻(aq)    Ksp₁ = (Ag⁺)²(CO₃²⁻)  

Ag₂CrO₄   ⇒  2 Ag⁺(aq)+ CrO₄²⁻(aq)   Ksp₂ = (Ag⁺)²(CrO₄²⁻)

Where (...) indicate concentrations M

Notice if we divide the expressions for Ksp we get:

Ksp₁/Ksp₂ = (CO₃²⁻)  / (CrO₄²⁻) = 8.5 x 10⁻¹² / 1.1 x 10⁻¹² = 7.7

which is the desired answer.

7 0
3 years ago
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