Answer:
Yes, acetic acid could be used, but it would not be as effective as acetyl chloride or acetic anhydride. ... However, the acetic anhydride would still be reacting with an alcohol, so nothing changes in that respect. Also, the reaction would need to be done in basic solution.
1.=b)
2.=b)
3.=a)
4.=a)
5.=d)
6.=a)
7=d)
Answer:
Ballistic is along the bottom
Answer:
The answer to your question is: 0.02
Explanation:
Data
Mass = 5.3 g of CaCl₂
Volume = 2.5 l
Molarity = ?
Formula
Molarity = ![\frac{moles}{volume}](https://tex.z-dn.net/?f=%5Cfrac%7Bmoles%7D%7Bvolume%7D)
Process
1.- Calculate the molecular mass of CaCl₂
Molecular mass = mass of Calcium + mass of chlorine
Molecular mass = 40 + 2(35.5)
= 40 + 71
= 111 g
2.- Calculate the mles of CaCl₂
111 g of CaCl₂ ------------------ 1 mol
5.3 g ------------------- x
x = (5.3 x 1) / 111
x = 0.048 moles
3.- Calculate molarity
Molarity = 0.048 / 2.5
Molarity = 0.02