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NISA [10]
3 years ago
13

PLEASE HELP

Chemistry
1 answer:
erastova [34]3 years ago
6 0

Answer:

Problem: The density of ethanol is 0.789 g/cm3 .What is its density in pounds per cubic inch ( lb/in3)?. Based on our data, ... 1 in = 2.54 cm. density = 0 . 789 g ...

Explanation:

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An atomic radius is about 1.00*10^2 pm. Convert the radius to inches. (1 pm=10^-12m)
natka813 [3]

Answer:

3.937 x 10⁻⁸ inches

Explanation:

Data Given:

Atomic radium in pm (picometer) = 1.00 x 10² pm

Atomic radium in inches = ?

1 pm = 10⁻¹² m

Solution:

First convert picometer to meter

As we Know

  1 pm = 10⁻¹² m

then

  1.00 x 10² pm = X meter

Do cross multiplication

        X meter = (1.00 x 10² pm)(10⁻¹² m) / 1 pm

       X meter = 1 x 10⁻⁹ m

So, 1.00 x 10² pm equal to 1 x 10⁻⁹ m

Now convert meter to inches

As

         1 m = 39.37 inches

         1 x 10⁻⁹ m = X inches

Do cross multiplication

        X inches = (39.3701 inches)(1 x 10⁻⁹ m ) / 1 m

        X inches = 3.937 x 10⁻⁸ inches

So,

1.00 x 10² pm = 3.937 x 10⁻⁸ inches

so the radius is 3.937 x 10⁻⁸ inches

4 0
3 years ago
Calculate the mass, in grams, of a single xenon atom (mxe = 131.29 amu ).
Mariana [72]

Answer is 2.18017\times10^{-22}gms.

Explanation: To calculate the mass of 1 Xe-atom , we will require atomic mass of Xe which is 131.29amu.

This atomic mass is the mass of 1 mole of 1 Xe-atom. One mole of Xe-atom is 6.022\times10^{23} atoms of Xe. We will use this relation to convert Mass of Xe-atom into grams.

\frac{\text{mass of 1 atom}}{atom}=\frac{\text{mass of 1 mole of atom}}{6.022\times10^{23}atoms}

\text{mass of 1 atom}=\frac{\text{mass of 1 mole of atom}}{6.022\times10^{23}}

\text{mass of 1 Xe-atom}=\frac{131.29}{6.022\times10^{23}}

\text{mass of 1-Xe atom}=21.8017\times10^{-23}gms

                                               =2.18017\times10^{-22}gms


5 0
3 years ago
According to the periodic table, which statement correctly describes the change from a neutral atom of an element to its ion?
Inessa [10]
A sodium atom forms NA+1 ion by losing two electrons 
7 0
3 years ago
Read 2 more answers
Which of the elements below has the highest ionization energy? Carbon, calcium, barium, or fluorine?
Serjik [45]
Fluorine has 1680 kJ/mol
6 0
3 years ago
1) The densities of air at −85°C, 0°C, and 100°C are 1.877 g dm−3, 1.294 g dm−3, and 0.946 g dm−3, respectively. From these data
earnstyle [38]

Answer:

1) The absolute zero temperature is -272.74 °C

2) The absolute zero temperature is -269.91°C

Explanation:

1) The specific volume of air at the given temperatures are;

At -85°C, v =  1/(1.877) = 0.533 dm³/g, the pressure =

At 0°C, v = 1/1.294 ≈ 0.773 dm³/g

At 100°C, v = 1/0.946 ≈ 1.057 dm³/g

We therefore have;

v₁ = 0.533 T₁ = 188.15  K

v₂ = 0.773 T₂ = 273.15  K

v₃ = 1.057 T₃ = 373.15  K

The slope of the graph formed by the above data is therefore given as follows;

m = (1.057 - 0.533)/(373.15 - 188.5) = 0.00284 dm³/K

The equation is therefor;

v - 0.533 = 0.00284×(T - 188.15)

v = 0.00284×T - 0.534 + 0.533  = 0.00284×T - 0.001167

v =  0.00284×T - 0.001167

Therefore, when the temperature, at absolute 0, we have;

v = 0

Which gives;

0 =  0.00284×T - 0.001167

0.00284×T = 0.001167

T = 0.001167/0.00284 ≈ 0.411 K

Which is 0.411  -273.15 ≈ -272.74 °C

The absolute zero temperature is -272.74 °C

2) The given volume of the gas = 20.00 dm³ at 0°C and 1.000 atm

The slope of the volume temperature graph at constant pressure = 0.0741 dm³/(°C)

The temperature is converted to Kelvin temperature, in order to apply Charles law as follows;

0°C = 0 + 273.15 K = 273.15 K

Therefore, the equation of the graph can be presented as follows;

v - 20.00 = 0.0741 × (T - 273.15)

Which gives;

v = 0.0741·T - 0.0741 ×(273.15) + 20

v = 0.0741·T - 20.2404125 + 20

v = 0.0741·T - 0.240415

Therefore at absolute 0, v = 0, we have;

0 = 0.0741·T - 0.240415

0.0741·T = 0.240415

T = 0.240415/0.0741 = 3.2445 K

The temperature in degrees is therefore;

3.2445 K - 273.15 ≈ -269.91°C

The absolute zero temperature is therefore, -269.91°C

3 0
3 years ago
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